Python max和min

Question

我对Python很陌生，让我对我的问题感到愤怒的是，我觉得它很简单。我在第8行继续收到错误。我只是希望这个程序能够获取用户输入的数字和打印最大和最小，如果它们输入负1，我希望它取消循环。

'int' object is not iterable是错误。

print "Welcome to The Number Input Program."

number = int(raw_input("Please enter a number: "))

while (number != int(-1)):
    number = int(raw_input("Please enter a number: "))

high = max(number)
low = min(number)

print "The highest number entered was ", high, ".\n"
print "The lowest number entered was ", low, ".\n"

raw_input("\n\nPress the enter key to exit.")

Answer 1

问题是number是int。 max和min都需要列表（或其他可迭代的内容） - 相反，您必须将number添加到列表中，如下所示：

number = int(raw_input("Please enter a number: "))
num_list = []

while (number != int(-1)):
    num_list.append(number)
    number = int(raw_input("Please enter a number: "))

high = max(num_list)
low = min(num_list)

在阅读jimbob博士答案后的一个注释 - 我的回答是假设您不想要在找到high和low时考虑-1。

Answer 2

这是因为每次将一个整数参数传递给max和min并且python不知道如何处理它。

Ether传递至少两个参数：

least_number = min(number1, number2,...,numbern)

或可迭代的：

least_number = min([number1, number2, ...,numbern])

这是doc

Answer 3

您需要将数字更改为数字列表。如，

print "Welcome to The Number Input Program."

numbers = []
number = int(raw_input("Please enter a number: "))

while (number != -1):
    numbers.append(number)
    number = int(raw_input("Please enter a number: "))

high = max(numbers)
low = min(numbers)

print "The highest number entered was ", high, ".\n"
print "The lowest number entered was ", low, ".\n"

raw_input("\n\nPress the enter key to exit.")

Answer 4

如another answer所述，min和max也可以使用多个参数。要省略列表，您可以

print "Welcome to The Number Input Program."

number = int(raw_input("Please enter a number: "))
high = low = number


while (number != int(-1)):
    number = int(raw_input("Please enter a number: "))
    high = max(high, number)
    low = min(low, number)

print "The highest number entered was ", high, ".\n"
print "The lowest number entered was ", low, ".\n"

raw_input("\n\nPress the enter key to exit.")

Answer 5

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