我的实施似乎不起作用。你能指出可能是什么问题或者指出一个更好的解决方案吗？当我选中复选框并单击删除按钮时，它似乎没有做任何事情......请帮助我。
<div id="container" class="page">
<img id="disclaimer" class="page" src="images/DISCLAIMER.png" alt="" />
<img id="logo" class="page" src="images/MI-LOGO.png" alt="" />
<div id="postItDiv" class="page">
<?php
$cxn = mysqli_connect('localhost', 'root', 'root', 'TimePost') or die(mysqli_error());
$query = "SELECT PostID, ClientName, VideoName, PostTime, Post, Date FROM tblTimePosts";
$result = mysqli_query($cxn, $query) or die(mysqli_error());
while($row = mysqli_fetch_assoc($result)) {
$post = $row['Post'];
$time = $row['PostTime'];
$idNo = $row['PostID'];
$postColor = rand(1, 4);
echo '<div id="post1"><p class="postParagraph">Post ID No.' . $idNo . '<br />' . $post . ' at ' . $time . ' seconds mark</p><div class="close"><form method="POST" action="videoJudge.php"><input type="checkbox" name="checkbox[]" id="checkbox[]" value="' . $idNo . '" /></form></div></div>';
}
if($_SERVER['REQUEST_METHOD'] == "POST" && $_POST['btnPost']) {
$postColors = rand(1, 4);
$toPost = $_POST['textPost'];
$date = date("y-m-d");
$postTime = $_POST['display'];
$postTime = floor($postTime);
$insertPostQuery = "INSERT INTO tblTimePosts VALUES('','Mimagazine Asia','Chelsea','$postTime','$toPost','$date')";
$query3 = "SELECT PostID FROM tblTimePosts";
$result = mysqli_query($cxn, $insertPostQuery) or die(mysqli_error());
$result3 = mysqli_query($cxn, $query3) or die(mysqli_error());
if($result > 0) {
while($row = mysqli_fetch_assoc($result3)) {
$idNo2 = $row['PostID'];
}
echo '<div id="post1"><p class="postParagraph">Post ID No.' . $idNo2 . '<br />' . $toPost . ' at ' . $postTime . ' seconds mark</p><div class="close"><form method="POST" action="videoJudge.php"><input type="checkbox" name="checkbox[]" id="checkbox[]" value="' . $idNo2 . '" /></form></div></div>';
}
else
echo "Add Failed";
}
/* if($_POST['chkDelete']) {
for($i=0;$i<5;$i++){
$del_id = $checkDelete[$i];
$sql = "DELETE FROM $tblTimePosts WHERE PostID='$del_id'";
$resulta = mysqli_query($cxn,$sql);
}
} */
if($_POST['btnDelete']) { // from button name="delete"
/* $checkbox = $_POST['checkbox']; //from name="checkbox[]"
$countCheck = count($_POST['checkbox']);
echo $countCheck;
for($i=0;$i<$countCheck;$i++){
$del_id = $checkbox[$i];
$sql = "DELETE FROM tblTimePosts WHERE PostID=".$del_id."";
$resulta = mysqli_query($cxn,$sql) or die(mysqli_error());
} */
$tbl_name = 'tblTimePosts';
foreach($_POST['checkbox'] as $id => $value) {
$sql = 'DELETE FROM `' . $tbl_name . '` WHERE `PostID`=' . (int) $id;
mysqli_query($cxn, $sql);
}
header('Location: videoJudge.php');
}
?>
</div>
<div id="videoContainer" class="page">
<video id="video" poster="images/cover.png" controls>
<source src="video/animationTest.m4v" />
</video>
</div>
<div id="etc" class="page">
<form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST">
<textarea name="textPost" id="textPost">
</textarea>
<input type="submit" name="btnPost" id="btnPost" value="Post" />
<div id="tae">
<input type="text" name="display" id="display" value="0" />
</div>
</form>
</div>
<div id="delButtonDiv">
<form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST">
<input type="submit" value="Delete" name="btnDelete" />
</form>
</div>
</div>
这是我的代码，现在你的所有评论之后，但仍然无法正常工作。 ：（
<?php
$cxn = mysqli_connect('localhost','root','root','TimePost') or die(mysqli_error());
$query = "SELECT PostID, ClientName, VideoName, PostTime, Post, Date FROM tblTimePosts";
$result = mysqli_query($cxn,$query) or die(mysqli_error());
while($row = mysqli_fetch_assoc($result)) {
$post = $row['Post'];
$time = $row['PostTime'];
$idNo = $row['PostID'];
$postColor = rand(1,4);
echo '<div id="post1"><p class="postParagraph">Post ID No.'.$idNo.'<br />'.$post.' at '.$time.' seconds mark</p><div class="close"><form method="POST" action="videoJudge.php"><input type="checkbox" name="checkbox[]" id="checkbox[]" value="'.$idNo.'" /></form>
</div></div>';
}
if ($_SERVER['REQUEST_METHOD'] == "POST" && $_POST['btnPost']) {
$toPost = $_POST['textPost'];
$date = date("y-m-d");
$postTime = $_POST['display'];
$postTime = floor($postTime);
$insertPostQuery = "INSERT INTO tblTimePosts VALUES('','Mimagazine Asia','Chelsea','$postTime','$toPost','$date')";
$query3 = "SELECT PostID FROM tblTimePosts";
$result = mysqli_query($cxn, $insertPostQuery) or die(mysqli_error());
$result3 = mysqli_query($cxn, $query3) or die(mysqli_error());
if ($result > 0) {
while($row = mysqli_fetch_assoc($result3)) {
$idNo2 = $row['PostID'];
}
echo '<div id="post1"><p class="postParagraph">Post ID No.'.$idNo2.'<br />'.$toPost.' at '.$postTime.' seconds mark</p><div class="close"><form method="POST" action="videoJudge.php"><input type="checkbox" name="checkbox[]" id="checkbox[]" value="'.$idNo2.'"
/></form></div></div>';
}
else
echo "Add Failed";
}
if($_POST['btnDelete'] == "Delete")
{
$tbl_name = 'tblTimePosts';
foreach ($_POST['checkbox'] as $id => $value)
{
$sql = 'DELETE FROM `'.$tbl_name.'` WHERE `PostID`='.(int)$id;
mysqli_query($cxn,$sql);
}
header('Location: videoJudge.php');
}
?>
</div>
<div id="videoContainer" class="page">
<video id="video" poster="images/cover.png" controls>
<source src="video/animationTest.m4v" />
</video>
</div>
<div id="etc" class="page">
<form action="<?php echo $_SERVER['PHP_SELF']?>" method="POST">
<textarea name="textPost" id="textPost">
</textarea>
<input type="submit" name="btnPost" id="btnPost" value="Post" />
<div id="tae">
<input type="text" name="display" id="display" value="0" />
</div>
<div id="delButtonDiv">
<input type="submit" value="Delete" name="btnDelete" />
</div>
</form>
</div>
答案 0 :(得分：2)
这样做可以解决问题，请尝试：
<div id="etc" class="page">
<form action="<?php $_SERVER['PHP_SELF']?>" method="POST">
<textarea name="textPost" id="textPost"></textarea>
<input type="submit" name="btnPost" id="btnPost" value="Post" />
<div id="tae">
<input type="text" name="display" id="display" value="0" />
</div>
<!-- END FORM REMOVED HERE -->
<!-- FORM REMOVED HERE -->
<div id="delButtonDiv"> <input type="submit" value="Delete" name="btnDelete" /> </div>
</form>
</div>
[EDITED]
您的表单中有两个提交按钮，然后您需要知道您正在采取的操作，POST或DELETE，对吗？然后你可以在你自己的php脚本中为你的帖子创建一个基本的控制器，如下所示：
这是表格 - ＆gt; <form action="<?php $_SERVER['PHP_SELF']?>" method="POST">
以下是提交按钮
<input type="submit" name="btnPost" id="btnPost" value="Post" />
<input type="submit" value="Delete" name="btnDelete" />
$_SERVER['PHP_SELF']告诉您它会将表单数据发送给自己，如果是，则在脚本的开头执行类似的操作：
if ($_POST[btnPost] == "Post")
// do some action to post the data
if ($_POST[btnDelete] == "Delete")
// do some action to delete the data
答案 1 :(得分：0)
您使用了两种表单，其中提交按钮属于第二种形式 当您按下提交按钮时，它只会提交一个空表格 将提交按钮移动到第一个表单应解决问题。
你有两行
<form action="<?php $_SERVER['PHP_SELF']?>" method="POST">
..
...
<form action="<?php $_SERVER['PHP_SELF']?>" method="POST">
删除第二个，
<form action="<?php $_SERVER['PHP_SELF']?>" method="POST">
^ missing an echo
如果您想要提交回相同的网址，则无需设置表单操作。
答案 2 :(得分：0)
删除按钮的位置必须与您前往提交的相同表单中的复选框一起使用。
<form method="POST" action="videoJudge.php" >
^______ url of the form you want to submit to. Possibly <?php echo $_SERVER['PHP_SELF']?>
<input type="checkbox" name="checkbox[]" id="checkbox[]" value="'.$idNo.'" />
<input type="submit" value="Delete" name="btnDelete" />
</form>