Question

我是iOS开发的新手。经过多次尝试;有很多示例代码，我设法从我的服务器解析一个json字符串，并能够在动态tableview中显示结果。我的问题是我无法使单元格可单击，因此他们会将id和标签传递给另一个视图，在该视图中将执行另一个json解析以显示该行的详细信息。

以下是我的代码：

#import "jsonviewcontroller.h"
#import "CJSONDeserializer.h"
#import "Otel_ItemViewController.h"

@implementation jsonviewcontroller


@synthesize tableview;
@synthesize rows;

- (void)dealloc {
    [rows release];
    [tableview release];
    [super dealloc];

}

// Customize the number of rows in the table view.
- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section {
    return [rows count];
}


// Customize the appearance of table view cells.
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {

    static NSString *CellIdentifier = @"Cell";

    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier];
    if (cell == nil) {
        cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle reuseIdentifier:CellIdentifier] autorelease];
    }

    // Configure the cell.
    NSDictionary *dict = [rows objectAtIndex: indexPath.row];

    cell.textLabel.text = [dict objectForKey:@"C_NAME"];
    cell.detailTextLabel.text = [dict objectForKey:@"CAT_ID"];


    return cell;
}

// Implement viewDidLoad to do additional setup after loading the view, typically from a nib.
- (void)viewDidLoad {
    [super viewDidLoad];
    NSURL *url = [NSURL URLWithString:@"http://zskript.net/categories.php"];
    NSString *jsonreturn = [[NSString alloc] initWithContentsOfURL:url];

    NSLog(jsonreturn); // Look at the console and you can see what the restults are

    NSData *jsonData = [jsonreturn dataUsingEncoding:NSUTF32BigEndianStringEncoding];
    NSError *error = nil;

    // In "real" code you should surround this with try and catch
    NSDictionary * dict = [[[CJSONDeserializer deserializer] deserializeAsDictionary:jsonData error:&error] retain];
    if (dict)
    {
        rows = [dict objectForKey:@"users"];
    }

    NSLog(@"Array: %@",rows);


    [jsonreturn release];
}

// Do some customisation of our new view when a table item has been selected
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
    // Make sure we're referring to the correct segue
    if ([[segue identifier] isEqualToString:@"ShowSelectedMovie"]) {

        // Get reference to the destination view controller
        Otel_ItemViewController *vc = [segue destinationViewController];

        // get the selected index
        NSInteger selectedIndex = [[self.tableview indexPathForSelectedRow] row];

        // Pass the name and index of our film
        [vc setSelectedItem:[NSString stringWithFormat:@"%@", [rows objectAtIndex:selectedIndex]]];
        [vc setSelectedIndex:selectedIndex];
    }
}


- (void)didReceiveMemoryWarning {
    // Releases the view if it doesn't have a superview.
    [super didReceiveMemoryWarning];

    // Release any cached data, images, etc that aren't in use.
}

- (void)viewDidUnload {
    // Release any retained subviews of the main view.
    // e.g. self.myOutlet = nil;
}



@end

以下是将显示详细信息的视图：

#import "Otel_ItemViewController.h"

@implementation Otel_ItemViewController

@synthesize selectedIndex, selectedItem;

- (void)viewDidLoad
{
    [super viewDidLoad];
    [outputLabel setText:selectedItem];
    [outputText setText:selectedItem];
    [outputImage setImage:[UIImage imageNamed:[NSString stringWithFormat:@"%d.jpg", selectedIndex]]];
}

@end

目前，当我单击表格中的单元格时，虽然我已将其设置为推送到下一个视图，但没有任何反应。有人请指教吗？

这是更新的代码。

我的根视图控制器：

    - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    NSDictionary *dict = [rows objectAtIndex: indexPath.row];
    DetailViewController *controller = [[DetailViewController alloc] init];
    controller.CATNAME = [dict objectForKey:@"C_NAME"];
    controller.CATNUMBER = [dict objectForKey:@"CAT_ID"];
    [self.navigationController pushViewController:controller animated:YES];
    [controller release];
}

这是DetailViewController.h：

@interface DetailViewController : UIViewController {


    NSString *CATNAME;
    NSInteger CATNUMBER;
    IBOutlet UILabel *labelId;
    IBOutlet UILabel *LabelName;

}

@property (nonatomic) NSInteger CATNUMBER;
@property (nonatomic, retain) NSString *CATNAME;

@end

和DetailViewController.m：

#import "DetailViewController.h"

@implementation DetailViewController

@synthesize CATNAME, CATNUMBER;


// Implement viewDidLoad to do additional setup after loading the view, typically from a nib.
- (void) viewDidLoad
{
    LabelName.Text = CATNAME;
    labelId = CATNUMBER;
//    [LabelName setText:CATNAME];
//    [labelId setText:CATNUMBER];
}

Answer 1

您必须实施此方法

编辑：加载新视图

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    NSDictionary *dict = [rows objectAtIndex: indexPath.row];
    MyNewViewController *controller = [[MyNewViewController alloc] init];
    controller.C_NAME = [dict objectForKey:@"C_NAME"];
    controller.CAT_ID = [dict objectForKey:@"CAT_ID"];
    [self.navigationController pushViewController:controller animated:YES];
    [controller release];
}

在上面的代码中，我假设您正在使用导航控制器（这是您想要做的事情的最简单方法）。另外我假设你有一个继承自UIViewController的类，你想要显示它。我还假设我在我的示例中调用MyNewViewController的这个类有两个成员和属性，分别称为C_NAME和CAT_ID。

- (void) viewDidLoad
{
     labelName.Text = C_NAME;
     labelId = CAT_ID
}

上面我的错误，因为我正在记忆中。但是主体保持不变，如果你正确地传递变量它应该可以工作，你可以查看我的blog它仍然需要做一些工作，但它有一个很好的初学者帖子并显示如何编辑标签的文字。在上面的代码中，我假设您的视图包含两个标签labelName和labelId。

在那里，您可以访问选择的单元格，然后您可以定义需要执行的操作。

TouchJSON如何使用json可点击填充表格？

1 个答案: