我有这个脚本,当我只使用一个OU时工作正常。但是,只要我将$ ldapbase放入一个数组并定义多个OU,它就会停止工作@ldap_get_entries和ldap_modify。我知道为什么但不确定如何相应地修改代码。
是否有办法分析整个林根,而不必定义OU,或只是获取samaccountname = $ username的OU。
<?php
$username=$_GET['username'];
if(isset($_POST['printpin'])) {
$printpin=$_POST['printpin'];
$domadlogin = 'admin@dom.co.uk';
$domadpw = 'pass';
$ldapServer = "dc.dom.co.uk";
$ldapBase[] = "OU=Users1,DC=dom,DC=co,DC=uk";
$ldapBase[] = "OU=Users2,DC=dom,DC=co,DC=uk";
$ldapBase[] = "OU=Users3,DC=dom,DC=co,DC=uk";
$ds = ldap_connect($ldapServer);
if (!$ds) {die('Cannot Connect to LDAP server');}
$ldapBind = ldap_bind($ds,$domadlogin,$domadpw);
if (!$ldapBind) {die('Cannot Bind to LDAP server');}
ldap_set_option($ds, LDAP_OPT_REFERRALS, 0);
ldap_set_option($ds, LDAP_OPT_PROTOCOL_VERSION, 3);
foreach($ldapBase as $dn){
$sr = ldap_search($ds, $dn, "(samaccountname=$username)");
}
$ent= ldap_get_entries($ds,$sr);
$dn=$ent[0]["dn"];
$newinfo['primaryTelexNumber']= $printpin;
$save = ldap_modify($ds, $dn, $newinfo);
if (!$save) {die('Cannot save to LDAP server');}
?>
<p>Your new PIN number has now been set.</p>
<p>Username: <?php echo $username; ?><br />PIN:<?php echo $printpin; ?></p>
<?php
}
else {
?>
<p>Username: <?php echo $username; ?></p>
<form action="pin.php?username=<?php echo $username; ?>" method="POST">
PIN: <input type="text" name="printpin" title="printpin"/>
<input type="hidden" name="username" value="<?php echo $username; ?>"/>
<input type="submit" value="Save">
</form>
<?php
}
?>
任何帮助都非常感激。
答案 0 :(得分:0)
您应该将更多代码移到 foreach 循环并添加一些类似的检查:
foreach ($ldapBase as $dn){
$sr = ldap_search($ds, $dn, "(samaccountname=$username)");
$ent = ldap_get_entries($ds, $sr);
if ($ent === false || $ent['count'] === 0)
continue;
$dn = $ent[0]['dn'];
$newinfo['primaryTelexNumber'] = $printpin;
$save = ldap_modify($ds, $dn, $newinfo);
if (!$save)
die('Cannot save to LDAP server');
break;
}
如果要搜索和修改所有OU,请在循环中删除最后一个中断。