Question

我正在使用linq查询来获取从某些指定类派生的所有类的所有属性的名称，如下所示：

    /// <summary>
    /// Gets all visible properties of classes deriving from the specified base type
    /// </summary>
    private HashSet<string> GetDerivedPropertyNames(Type baseType)
    {
        // get all property names of the properties of types that derive from the base type
        var propertyNames =
            from type in baseType.Assembly.GetTypes()
            where type.IsSubclassOf(baseType)
            select Array.ConvertAll(type.GetProperties(), property => property.Name);
        // the hashset constructor will filter out all duplicate property names
        return new HashSet<string>(propertyNames);
    }

但是这不能编译，因为linq查询的结果是IEnumerable<string[]>，而我想要IEnumerable<string>。如何将结果展平为单个IEnumerable<string>？

Answer 1

我认为你想要SelectMany：

var propertyNames = baseType.Assembly.GetTypes()
 .Where(type => type.IsSubclassOf(baseType))
 .SelectMany(type => type.GetProperties().Select(property => property.Name));

可能一次包括“明显”步骤：

var propertyNames = baseType.Assembly.GetTypes()
 .Where(type => type.IsSubclassOf(baseType))
 .SelectMany(type => type.GetProperties().Select(property => property.Name))
 .Distinct();

从linq查询中展平结果

1 个答案: