在intel assembly nasm中输出许多字符串

Question

我正在尝试输出许多字符串。我在互联网上找到了这个简单的hello world程序，它输出一个存储在内存中的字符串：

;  hello.asm  a first program for nasm for Linux, Intel, gcc
;
; assemble: nasm -f elf -l hello.lst  hello.asm
; link:     gcc -o hello  hello.o
; run:          hello 
; output is:    Hello World 

SECTION .data       ; data section
msg:    db "Hello World",10 ; the string to print, 10=cr
len:    equ $-msg       ; "$" means "here"
            ; len is a value, not an address

SECTION .text       ; code section
    global main     ; make label available to linker 
main:               ; standard  gcc  entry point

mov edx,len     ; arg3, length of string to print
mov ecx,msg     ; arg2, pointer to string
mov ebx,1       ; arg1, where to write, screen
mov eax,4       ; write command to int 80 hex
int 0x80        ; interrupt 80 hex, call kernel

mov ebx,0       ; exit code, 0=normal
mov eax,1       ; exit command to kernel
int 0x80        ; interrupt 80 hex, call kernel

这很有效。 现在我修改它以放入两个字符串。

    SECTION .data       ; data section
 msg:   db "Hello World",10 ; the string to print, 10=cr
 len:   equ $-msg       ; "$" means "here"
 msg2:  db "Hello World2",10    ; the string to print, 10=cr
 len2:  equ $-msg2      ; "$" means "here"
  mov   edx,len       ; arg3, length of string to print
    mov ecx,msg     ; arg2, pointer to string
    mov ebx,1       ; arg1, where to write, screen
    mov eax,4         ; write sysout command to int 80 hex
    int 0x80        ; interrupt 80 hex, call kernel



    mov edx,len2          ; arg3, length of string to print
    mov ecx,msg2        ; arg2, pointer to string
    mov ebx,1       ; arg1, where to write, screen
  mov   eax,4         ; write sysout command to int 80 hex
    int 0x80        ; interrupt 80 hex, call kernel

这不起作用，因为它输出第二个字符串两次。