Question

我对boost :: spirit / fusion很新。有人可以向我解释为什么以下不编译？如果我将m_name和m_settings变量直接放在config结构中，它正在编译和工作正常，但是当我将它们分成两个不同的结构时无法编译。我错过了什么？

顺便说一下，使编译器喷出大量boost::spirit errors is: cfg = section >> node;

的代码行

#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/spirit/include/phoenix_fusion.hpp>
#include <boost/spirit/include/phoenix_stl.hpp>
#include <boost/fusion/include/adapt_struct.hpp>

#include <iostream>
#include <string>
#include <vector>

namespace qi = boost::spirit::qi;
namespace fusion = boost::fusion;
namespace phoenix = boost::phoenix;
namespace ascii = boost::spirit::ascii;

struct config_section
{
  std::string m_name;
  std::string m_settings;
};

struct config
{
  config_section m_sections;
};

BOOST_FUSION_ADAPT_STRUCT(
    config_section,
    (std::string, m_name)
    (std::string, m_settings)
)

BOOST_FUSION_ADAPT_STRUCT(
    config,
    (config_section, m_sections)
)

template <typename Iterator>
struct config_grammar : qi::grammar<Iterator, config(), ascii::space_type>
{
  config_grammar() : config_grammar::base_type(cfg)
  {
    using qi::lexeme;
    using qi::lit;
    using ascii::string;
    using ascii::char_;
    using namespace qi::labels;

    section %= '[' >> lexeme[+(char_ - ']')] >> ']';

    node %= !lit('[') >> lexeme[+(char_ - '\n')];

    cfg %= section >> node;
  }

  qi::rule<Iterator, config(), ascii::space_type> cfg;
  qi::rule<Iterator, std::string(), ascii::space_type> node;
  qi::rule<Iterator, std::string(), ascii::space_type> section;
};

template <typename Iterator>
bool parse_config(Iterator first, Iterator last)
{
  using qi::double_;
  using qi::phrase_parse;
  using ascii::space;
  using boost::phoenix::ref;

  config result;
  config_grammar<Iterator> config_parser;

  bool r = phrase_parse(first, last, config_parser, space, result);
  if (first != last) // fail if we did not get a full match
    return false;

  return r;
}

int main()
{
  std::string input = "[section]\nstuff";

  bool b = parse_config(input.begin(), input.end());

  if (b)
    std::cout << "Success" << std::endl;
  else
    std::cout << "Failure" << std::endl;

  return 0;
}

谢谢！

Answer 1

问题似乎是您没有指定如何从config_section转换为配置。你告诉精神，config_section由2个字符串组成，但尝试解析配置而没有规则来链接config和config_section之间的转换。这似乎是编译。

template <typename Iterator>
struct config_grammar : qi::grammar<Iterator, config(), ascii::space_type>
{
  config_grammar() : config_grammar::base_type(cfg)
  {
    using qi::lexeme;
    using qi::lit;
    using ascii::string;
    using ascii::char_;
    using namespace qi::labels;

    section %= '[' >> lexeme[+(char_ - ']')] >> ']';

    node %= !lit('[') >> lexeme[+(char_ - '\n')];

    //create a rule to specify conversion of a config_section to a config
    cfg %= cfg_sec;
    //this a now a cfg_sec (which is what you declared to be composed of 2
    //  strings)
    cfg_sec %= section >> node;
  }

  qi::rule<Iterator, config(), ascii::space_type> cfg;
  //add new declaration here for cfg_sec
  qi::rule<Iterator, config_section(), ascii::space_type> cfg_sec;
  qi::rule<Iterator, std::string(), ascii::space_type> node;
  qi::rule<Iterator, std::string(), ascii::space_type> section;
};

Answer 2

问题是cfg规则和config_grammar语法的属性不是config，而是（据我所知 - 因为它是两个结果字符串）{ {1}}。在此替换之后：

config_section

它编译。</ p>

我建议你更多地了解规则的属性及其工作原理 - 否则你会一直迷路。

使用BOOST_FUSION_ADAPT_STRUCT的boost :: spirit编译问题

2 个答案: