我一直在努力解决Castle ActiveRecord异常问题。每当我尝试访问数据库时，我都会得到一个InnerException值为"An attempt to attach an auto-named database for file database.mdf failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share."
我正在尝试连接到SQL Server Express 2005数据库。我没有任何其他数据库选项，因为学校计算机上只有SQL Express。
我的连接设置
hibernate.connection.driver_class
NHibernate.Driver.SqlClientDriver
hibernate.dialect
NHibernate.Dialect.MsSql2005Dialect
hibernate.connection.provider
NHibernate.Connection.DriverConnectionProvider
hibernate.connection.connection_string
Data Source=.\SQLExpress;Integrated Security=True;User Instance=True;AttachDBFilename=database.mdf
即使我将AttachDBFilename设置为绝对路径，也无法工作。用户实例无效。数据库文件当前位于与我的WinForms类混合的项目的根目录中。
使用时
hibernate.connection.connection_string
Data Source=localhost;Initial Catalog=FinalApp;Integrated Security=True;Pooling=False
我在笔记本电脑上执行此操作时没有问题，但我无法在学校计算机上使用SQL Server 2005 Developer Edition。
按要求提供完整堆栈跟踪
Castle.ActiveRecord.Framework.ActiveRecordException was unhandled
Message="Could not perform FindAll for Book"
Source="Castle.ActiveRecord"
StackTrace:
at Castle.ActiveRecord.ActiveRecordBase.FindAll(Type targetType, Order[] orders, ICriterion[] criteria) in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordBase.cs:line 1022
at Castle.ActiveRecord.ActiveRecordBase.FindAll(Type targetType) in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordBase.cs:line 982
at Castle.ActiveRecord.ActiveRecordBase`1.FindAll() in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordBase.Generic.cs:line 333
at CSharpFinal.InventoryMain.InventoryMain_Load(Object sender, EventArgs e) in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\InventoryMain.cs:line 36
at System.Windows.Forms.Form.OnLoad(EventArgs e)
at System.Windows.Forms.Form.OnCreateControl()
at System.Windows.Forms.Control.CreateControl(Boolean fIgnoreVisible)
at System.Windows.Forms.Control.CreateControl()
at System.Windows.Forms.Control.WmShowWindow(Message& m)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ContainerControl.WndProc(Message& m)
at System.Windows.Forms.Form.WmShowWindow(Message& m)
at System.Windows.Forms.Form.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.SafeNativeMethods.ShowWindow(HandleRef hWnd, Int32 nCmdShow)
at System.Windows.Forms.Control.SetVisibleCore(Boolean value)
at System.Windows.Forms.Form.SetVisibleCore(Boolean value)
at System.Windows.Forms.Control.Show()
at CSharpFinal.Form1.inventoryToolStripMenuItem_Click(Object sender, EventArgs e) in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Form1.cs:line 51
at System.Windows.Forms.ToolStripItem.RaiseEvent(Object key, EventArgs e)
at System.Windows.Forms.ToolStripMenuItem.OnClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleMouseUp(MouseEventArgs e)
at System.Windows.Forms.ToolStripItem.FireEventInteractive(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStripItem.FireEvent(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStrip.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.ToolStripDropDown.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ToolStrip.WndProc(Message& m)
at System.Windows.Forms.ToolStripDropDown.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg)
at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(Int32 dwComponentID, Int32 reason, Int32 pvLoopData)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.Run(Form mainForm)
at CSharpFinal.Program.Main() in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Program.cs:line 17
at System.AppDomain.nExecuteAssembly(Assembly assembly, String[] args)
at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
at System.Threading.ThreadHelper.ThreadStart()
Castle.ActiveRecord.Framework.ActiveRecordException was unhandled
Message="Could not create the schema"
Source="Castle.ActiveRecord"
StackTrace:
at Castle.ActiveRecord.ActiveRecordStarter.CreateSchema() in c:\dev\castle\svn\branches\1.0.x\ActiveRecord\Castle.ActiveRecord\Framework\ActiveRecordStarter.cs:line 212
at CSharpFinal.Form1.reInitializeDatabaseToolStripMenuItem_Click(Object sender, EventArgs e) in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Form1.cs:line 65
at System.Windows.Forms.ToolStripItem.RaiseEvent(Object key, EventArgs e)
at System.Windows.Forms.ToolStripMenuItem.OnClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleClick(EventArgs e)
at System.Windows.Forms.ToolStripItem.HandleMouseUp(MouseEventArgs e)
at System.Windows.Forms.ToolStripItem.FireEventInteractive(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStripItem.FireEvent(EventArgs e, ToolStripItemEventType met)
at System.Windows.Forms.ToolStrip.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.ToolStripDropDown.OnMouseUp(MouseEventArgs mea)
at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ToolStrip.WndProc(Message& m)
at System.Windows.Forms.ToolStripDropDown.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)
at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg)
at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(Int32 dwComponentID, Int32 reason, Int32 pvLoopData)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context)
at System.Windows.Forms.Application.Run(Form mainForm)
at CSharpFinal.Program.Main() in C:\Documents and Settings\Administrator\My Documents\Visual Studio 2005\Projects\CSharpFinal\Program.cs:line 17
at System.AppDomain.nExecuteAssembly(Assembly assembly, String[] args)
at System.AppDomain.ExecuteAssembly(String assemblyFile, Evidence assemblySecurity, String[] args)
at Microsoft.VisualStudio.HostingProcess.HostProc.RunUsersAssembly()
at System.Threading.ThreadHelper.ThreadStart_Context(Object state)
at System.Threading.ExecutionContext.Run(ExecutionContext executionContext, ContextCallback callback, Object state)
at System.Threading.ThreadHelper.ThreadStart()
InnerException.Message是"An attempt to attach an auto-named database for file database.mdf failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share."
答案 0 :(得分：0)
这可能是因为您的SQL Express连接字符串正在关闭用户实例。如果您打开用户实例，则SQL将根据需要附加数据库，否则只会打开它。如果你将其关闭，那么附件就是永久性的。任何再次使用相同连接字符串的尝试都将导致错误，因为数据库已存在 如果您没有使用该连接字符串附加数据库，则需要先分离数据库，然后才能使用正确的连接字符串。 我建议你下载SQL管理工作室快递，如果你还没有得到它。这将让您看到已附加的数据库并轻松分离。
好的，如果那不是问题，SQL服务器可以访问数据库文件吗？它是否获得该文件夹的权限？它通常作为网络服务运行，您可以像任何其他用户一样授予对文件的访问权限。您可以通过向所有人授予完全控制权来消除文件权限，如果修复了它，那么您可以将权限调整到所需的权限。我猜想SQL服务器服务帐户将需要修改.mdf文件的权限。我不知道它为用户实例数据库创建.ldf的位置。它可能需要在与.mdf相同的文件夹中创建文件权限。
答案 1 :(得分：0)