我正在尝试使用Django学习一些基本的ajax。我的简单项目是一个应用程序，它从数据库中的可用奖品中随机选择Prize，减少其数量，然后将prize.name返回到页面。
我正在使用jQuery的$ .ajax方法来解决这个问题。唯一正在运行的是我的$ .ajax调用中定义的error函数，但错误消息只显示“错误”。我是ajax的新手，所以我可能会忽略一些显而易见的事情。这是相关的代码：
class Prize(models.Model):
name = models.CharField(max_length=50)
quantity = models.IntegerField(default=0)
def __unicode__(self):
return self.name
urlpatterns = patterns('',
(r'^get_prize/$', 'app.views.get_prize' ),
)
def get_prize(request):
prizes = Prize.objects.filter(quantity__gt=0)
to_return = {}
if prizes:
rand = random.randrange(len(prizes))
prize = prizes[rand]
prize.quantity -= 1
prize.save()
to_return['prize'] = prize.name
data = simplejson.dumps(to_return)
return HttpResponse(data, mimetype='application/json')
else:
to_return['msg'] = "That's all the prizes. No more."
data = simplejson.dumps(to_return)
return HttpResponse(data, mimetype='application/json')
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>User's Conference Prize Randomizer</title>
<link rel="stylesheet" type="text/css" href="/static-media/style.css" />
<script type="text/javascript" src="/static-media/jquery-1.2.6.min.js"></script>
<script type="text/javascript">
var get_prize = function() {
var args = {
type: "GET",
url: "get_prize",
dataType: "json",
success: done,
error: function(response,error_string,e){
alert( "Error: " + response.responseText + " " + error_string );
for (i in e){
alert(i);
}
}
};
$.ajax(args);
};
var done = function(response) {
if(response) {
alert(response);
}
else {
alert("Something boo-booed");
}
};
$(document).ready(function() {
$("#start").click(get_prize);
});
</script>
</head >
<body>
<p><a href="" id='start'>Get Prize</a>, this link isn't working how I'd like.</p>
</body>
答案 0 :(得分：1)
这与您的问题并不完全相关，但如果您尝试从数据库中获取随机对象，则可以改为：
prize = Prize.objects.filter(quantity__gt=0).order_by('?')[:1]
if prize:
prize = prize[0]
# Using a slice prevents an exception if the query returns an empty queryset.
# If you're not a fan of LBYL, you could wrap the query in a try...except block instead:
try:
prize = Prize.objects.filter(quantity__gt=0).order_by('?')[0]
except IndexError:
# No more prizes pal...done, fini.
答案 1 :(得分：0)
这不是你问题的直接答案，但你看过jQuery taconite插件吗？它使得大多数AJAXy的东西变得微不足道。有关malup's taconite page的更多信息。当你在这里时，请查看他的other excellent plugins。
答案 2 :(得分：0)
好悲伤。我刚刚在进行ajax调用的函数中省略了return false。去n00b的路。 ：0