Question

我想知道将Excel工作表列名转换为数字的最佳方法是什么。

我正在使用Excel Package，一个很好的库来处理.xlsx文档。遗憾的是，这个库没有包含此功能。

OBS：第一列A对应在这个图书馆中排名第一。

Answer 1

此函数应适用于任意长度的列名。

public static int GetColumnNumber(string name)
{
    int number = 0;
    int pow = 1;
    for (int i = name.Length - 1; i >= 0; i--)
    {
        number += (name[i] - 'A' + 1) * pow;
        pow *= 26;
    }

    return number;
}

Answer 2

几个月前我不得不处理这件事。列名的反列索引 - 也很有趣，如果你尝试用基于零的索引解决它而不是认识到这会使事情复杂化，那就变得非常麻烦。如果它是一个普通的多元数字系统就可以这么简单......

以下是我的解决方案的简化版本作为扩展方法，没有错误处理和所有这些。

public static Int32 ToOneBasedIndex(this String name)
{
    return name.ToUpper().
       Aggregate(0, (column, letter) => 26 * column + letter - 'A' + 1);
}

Answer 3

我已经使用了一段时间了，发现这对于超越AZ，甚至超出AA-ZZ的列非常有用......它是通过分解字符串中的每个字符并递归调用来实现的本身导出ASCII字符的DEC值（小于64），然后乘以26 ^ n。当n> 1时，使用long的返回值来克服潜在的限制。 4。

    public long columnNumber(String columnName)
    {
        char[] chars = columnName.ToUpper().ToCharArray();

        return (long)(Math.Pow(26, chars.Count() - 1)) * 
            (System.Convert.ToInt32(chars[0]) - 64) + 
            ((chars.Count() > 2) ? columnNumber(columnName.Substring(1, columnName.Length - 1)) : 
            ((chars.Count() == 2) ? (System.Convert.ToInt32(chars[chars.Count() - 1]) - 64) : 0));
    }

另外，如果您想获得反转（即传入columnNumber并获取columnName，这里有一些适用于此的代码。

    public String columnName(long columnNumber)
    {
        StringBuilder retVal = new StringBuilder();
        int x = 0;

        for (int n = (int)(Math.Log(25*(columnNumber + 1))/Math.Log(26)) - 1; n >= 0; n--)
        {
            x = (int)((Math.Pow(26,(n + 1)) - 1) / 25 - 1);
            if (columnNumber > x)
                retVal.Append(System.Convert.ToChar((int)(((columnNumber - x - 1) / Math.Pow(26, n)) % 26 + 65)));
        }

        return retVal.ToString();
    }

Answer 4

源代码：

namespace XLS
{
/// <summary>
/// Represents a single cell in a excell sheet
/// </summary>
public struct Cell
{
    private long row;
    private long column;
    private string columnAddress;
    private string address;
    private bool dataChange;

    /// <summary>
    /// Initializes a new instance of the XLS.Cell 
    /// class with the specified row and column of excel worksheet
    /// </summary>
    /// <param name="row">The row index of a cell</param>
    /// <param name="column">The column index of a cell</param>
    public Cell(long row, long column)
    {
        this.row = row;
        this.column = column;
        dataChange = true;
        address = string.Empty;
        columnAddress = string.Empty;
    }

    /// <summary>
    /// Initializes a new instance of the XLS.Cell
    /// class with the specified address of excel worksheet
    /// </summary>
    /// <param name="address">The adress of a cell</param>
    public Cell(string address)
    {
        this.address = address;
        dataChange = false;
        row = GetRow(address);
        columnAddress = GetColumnAddress(address);
        column = GetColumn(columnAddress);
    }

    /// <summary>
    /// Gets or sets the row of this XLS.Cell
    /// </summary>
    public long Row
    {
        get { return row <= 0 ? 1 : row; }
        set { row = value; dataChange = true; }
    }

    /// <summary>
    /// Gets or sets the column of this XLS.Cell
    /// </summary>
    public long Column
    {
        get { return column <= 0 ? 1 : column; }
        set { column = value; dataChange = true; }
    }

    /// <summary>
    /// Gets or sets the address of this XLS.Cell
    /// </summary>
    public string Address
    {
        get { return dataChange ? ToAddress() : address; }
        set
        {
            address = value;
            row = GetRow(address);
            column = GetColumn(address);
        }
    }

    /// <summary>
    /// Gets the column address of this XLS.Cell
    /// </summary>
    public string ColumnAddress
    {
        get { return GetColumnAddress(Address); }
        private set { columnAddress = value; }
    }

    #region Private Methods

    private static long GetRow(string address)
    {
        return long.Parse(address.Substring(GetStartIndex(address)));
    }

    private static string GetColumnAddress(string address)
    {
        return address.Substring(0, GetStartIndex(address)).ToUpperInvariant();
    }

    private static long GetColumn(string columnAddress)
    {
        char[] characters = columnAddress.ToCharArray();
        int sum = 0;
        for (int i = 0; i < characters.Length; i++)
        {
            sum *= 26;
            sum += (characters[i] - 'A' + 1);
        }

        return (long)sum;
    }

    private static int GetStartIndex(string address)
    {
        return address.IndexOfAny("123456789".ToCharArray());
    }

    private string ToAddress()
    {
        string indexToString = string.Empty;

        if (Column > 26)
        {
            indexToString = ((char)(65 + (int)((Column - 1) / 26) - 1)).ToString();
        }

        indexToString += (char)(65 + ((Column - 1) % 26));

        dataChange = false;
        return indexToString + Row;
    }

    #endregion
}

}

Answer 5

O24有一个列号，你想要一个名字：

= LEFT（RIGHT（ADDRESS（1，O24），LEN（ADDRESS（1，O24）） - 1），FIND（ “$”，RIGHT（（ADDRESS（1，O24）），LEN（ADDRESS（1 ，O24）） - 1）） - 1）

O37有一个列名，你想要一个数字：

= COLUMN（INDIRECT（O37＆安培; 1））

Answer 6

public static string GetColumnName(int index)
{
    const string letters = "ZABCDEFGHIJKLMNOPQRSTUVWXY";

    int NextPos = (index / 26);
    int LastPos = (index % 26);
    if (LastPos == 0) NextPos--;

    if (index > 26)
        return GetColumnName(NextPos) + letters[LastPos];
    else
        return letters[LastPos] + "";
}

如何将Excel工作表列名转换为数字？

6 个答案: