Question

我正在以编程方式创建.idl文件。如何以编程方式为接口和方法创建UUID。

我可以通过编程方式生成UUID吗？

Answer 1

您可能正在寻找System.Guid.NewGuid()。

Answer 2

注意：虽然.NET Guid和（RFC4122）UUID的字符串表示相同，但the storage format is not. .NET以前端三个Guid部分的小端字节进行交易。

如果要传输字节（例如，作为base64），则不能只使用Guid.ToByteArray()并对其进行编码。您需要Array.Reverse前三个部分（Data1-3）。

我是这样做的：

var rfc4122bytes = Convert.FromBase64String("aguidthatIgotonthewire==");
Array.Reverse(rfc4122bytes,0,4);
Array.Reverse(rfc4122bytes,4,2);
Array.Reverse(rfc4122bytes,6,2);
var guid = new Guid(rfc4122bytes);

有关特定的.NET实现详细信息，请参阅this answer。

编辑：感谢Code Ranger的Jeff Walker指出内部与进出字节数组构造函数的字节数组的格式无关，{{ 1}}。

Answer 3

这是客户端“顺序指导”解决方案。

http://www.pinvoke.net/default.aspx/rpcrt4.uuidcreate

using System;
using System.Runtime.InteropServices;


namespace MyCompany.MyTechnology.Framework.CrossDomain.GuidExtend
{
    public static class Guid
    {

        /*

        Original Reference for Code:
        http://www.pinvoke.net/default.aspx/rpcrt4/UuidCreateSequential.html

        */


        [DllImport("rpcrt4.dll", SetLastError = true)]
        static extern int UuidCreateSequential(out System.Guid guid);

        public static System.Guid NewGuid()
        {
            return CreateSequentialUuid();
        }


        public static System.Guid CreateSequentialUuid()
        {
            const int RPC_S_OK = 0;
            System.Guid g;
            int hr = UuidCreateSequential(out g);
            if (hr != RPC_S_OK)
                throw new ApplicationException("UuidCreateSequential failed: " + hr);
            return g;
        }


        /*

        Text From URL above:

        UuidCreateSequential (rpcrt4)

        Type a page name and press Enter. You'll jump to the page if it exists, or you can create it if it doesn't.
        To create a page in a module other than rpcrt4, prefix the name with the module name and a period.
        . Summary
        Creates a new UUID 
        C# Signature:
        [DllImport("rpcrt4.dll", SetLastError=true)]
        static extern int UuidCreateSequential(out Guid guid);


        VB Signature:
        Declare Function UuidCreateSequential Lib "rpcrt4.dll" (ByRef id As Guid) As Integer


        User-Defined Types:
        None.

        Notes:
        Microsoft changed the UuidCreate function so it no longer uses the machine's MAC address as part of the UUID. Since CoCreateGuid calls UuidCreate to get its GUID, its output also changed. If you still like the GUIDs to be generated in sequential order (helpful for keeping a related group of GUIDs together in the system registry), you can use the UuidCreateSequential function.

        CoCreateGuid generates random-looking GUIDs like these:

        92E60A8A-2A99-4F53-9A71-AC69BD7E4D75
        BB88FD63-DAC2-4B15-8ADF-1D502E64B92F
        28F8800C-C804-4F0F-B6F1-24BFC4D4EE80
        EBD133A6-6CF3-4ADA-B723-A8177B70D268
        B10A35C0-F012-4EC1-9D24-3CC91D2B7122



        UuidCreateSequential generates sequential GUIDs like these:

        19F287B4-8830-11D9-8BFC-000CF1ADC5B7
        19F287B5-8830-11D9-8BFC-000CF1ADC5B7
        19F287B6-8830-11D9-8BFC-000CF1ADC5B7
        19F287B7-8830-11D9-8BFC-000CF1ADC5B7
        19F287B8-8830-11D9-8BFC-000CF1ADC5B7



        Here is a summary of the differences in the output of UuidCreateSequential:

        The last six bytes reveal your MAC address 
        Several GUIDs generated in a row are sequential 
        Tips & Tricks:
        Please add some!

        Sample Code in C#:
        static Guid UuidCreateSequential()
        {
           const int RPC_S_OK = 0;
           Guid g;
           int hr = UuidCreateSequential(out g);
           if (hr != RPC_S_OK)
             throw new ApplicationException
               ("UuidCreateSequential failed: " + hr);
           return g;
        }



        Sample Code in VB:
        Sub Main()
           Dim myId As Guid
           Dim code As Integer
           code = UuidCreateSequential(myId)
           If code <> 0 Then
             Console.WriteLine("UuidCreateSequential failed: {0}", code)
           Else
             Console.WriteLine(myId)
           End If
        End Sub




        */








    }
}

关键字：CreateSequentialUUID SequentialUUID

Answer 4

我不知道方法;但是，GUID的类型可以通过以下方式完成：

Guid iid = System.Runtime.InteropServices.Marshal.GenerateGuidForType(typeof(IFoo));

http://msdn.microsoft.com/en-us/library/system.runtime.interopservices.marshal.generateguidfortype.aspx

Answer 5

我在C＃中有一个像Java一样的UUID实现的GitHub Gist： https://gist.github.com/rickbeerendonk/13655dd24ec574954366

UUID可以从最低和最高位创建，就像在Java中一样。它也揭露了它们。该实现具有显式转换为GUID和来自GUID的隐式转换。

如何在C＃中生成UUID

5 个答案: