Question

我有一个字符串模式，如＆＃34; test＆＃34; ：＆＃34; abc / gef fhhff / fhrhr krerjr＆＃34;，

我想替换以＆＃34; test＆＃34;开头的行中的所有空格。加号。如何使用正则表达式？

Answer 1

在perl中，您必须执行以下操作：

use strict;
use warnings;

use 5.010;

my $text = q|test : "abc/gef fhhff/fhrhr krerjr"|;

#below is the regex that does the replace - \s is for whitespace class
$text =~ s/\s/+/gmix if ( $text =~ /^test/gmix);

say "new text: $text";

Answer 2

for vb net try

        Dim strCurrentLine as string = "test : abc/gef fhhff/fhrhr krerjr"

        If UCase(strCurrentLine.ToString.StartsWith("TEST")) = True Then
            strCurrentLine = Replace(strCurrentLine.ToString, " ", "Replace space with this text")
        End If

for C＃try

    string strCurrentLine = "test : abc/gef fhhff/fhrhr krerjr";

    if (Strings.UCase(strCurrentLine.ToString().StartsWith("TEST")) == true) {
        strCurrentLine = Strings.Replace(strCurrentLine.ToString(), " ", "Replace space with this text");
    }

或者转到vb正则表达式http://visualbasic.about.com/od/usingvbnet/a/RegExNET_2.htm

或者去c＃regex http://oreilly.com/windows/archive/csharp-regular-expressions.html

如何实现查找和替换以下任务？

2 个答案: