如何在发布到PHP文件后从HttpResponse对象中检索字符串?

时间:2011-12-11 17:58:21

标签: java android post entity httpresponse

我想在android中使用HTTP-post后检索php文件发回的数据。我的代码如下所示:

HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://10.0.2.2/post.php");
List <NameValuePair> pairs = new ArrayList<NameValuePair>();
pairs.add(new BasicNameValuePair("test", "hejsan"));

try{
    post.setEntity(new UrlEncodedFormEntity(pairs));
}catch(UnsupportedEncodingException a){
        infoText.setText("failed to post");
}

try{
        HttpResponse response = client.execute(post);
        infoText.setText(response.getEntity().toString());
}catch(ClientProtocolException b){
        infoText.setText("failed to get response");
}catch(IOException e){
        infoText.setText("failed IOEXCEPTION");
}this code only changes the "TextView" to: org.apache.http.conn

BasicManagedEntity @ 45f94a68 ...我的php文件非常简单,它只回显文本“data”。我认为这个问题与“response.getEntity()。toString()”有关但是如何从HttpPost对象中获取作为字符串发回的数据?

原谅我的拼写错误。

2 个答案:

答案 0 :(得分:0)

您可以使用响应处理程序..这样的事情:

public static String getResponseBody(HttpResponse response) {
    ResponseHandler<String> responseHander = new BasicResponseHandler();
    String responseBody = null;
    try {
        responseBody = (String) responseHander.handleResponse(response);
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    logger.debug("Response Body Data:" + responseBody);

    return responseBody;
}

答案 1 :(得分:0)

您也可以使用EntityUtils:

String responseBody = EntityUtils.toString(response.getEntity());