我有这些数组:
$ ARRAY1
Array
(
[0] => Array
(
[state] => AE
[state_pri] => 0
)
[1] => Array
(
[state] => AK
[state_pri] => 0
)
[2] => Array
(
[state] => AL
[state_pri] => 0
)
)
$数组2
Array
(
[0] => Array
(
[0] => Array
(
[count1] => 0
)
)
[1] => Array
(
[0] => Array
(
[count1] => 1
)
)
[2] => Array
(
[0] => Array
(
[count1] => 18
)
)
)
$ ARRAY3
Array
(
[0] => Array
(
[0] => Array
(
[count] => 0
)
)
[1] => Array
(
[0] => Array
(
[count] => 1
)
)
[2] => Array
(
[0] => Array
(
[count] => 18
)
)
)
......我想得到这样的东西:
Array
(
[0] => Array
(
[state] => AE
[state_pri] => 0
[0] => Array
(
[count] => 0
)
[0] => Array
(
[count1] => 0
)
)
[1] => Array
(
[state] => AK
[state_pri] => 0
[1] => Array
(
[count] => 0
)
[1] => Array
(
[count1] => 0
)
)
[2] => Array
(
[state] => AL
[state_pri] => 0
[2] => Array
(
[count] => 0
)
[2] => Array
(
[count1] => 0
)
)
)
关于如何做到这一点的任何想法?
编辑:只是为了添加更多代码,如果我使用array_merge
,我会得到:
Array
(
[0] => Array
(
[state] => AE
[state_pri] => 0
)
[1] => Array
(
[state] => AK
[state_pri] => 0
)
[2] => Array
(
[state] => AL
[state_pri] => 0
)
[3] => Array
(
[0] => Array
(
[count] => 0
)
)
[4] => Array
(
[0] => Array
(
[count] => 1
)
)
[5] => Array
(
[0] => Array
(
[count] => 18
)
)
.....
)
答案 0 :(得分:1)
你要找的东西仍然有点难以辨认。如果这能达到预期效果,请告诉我们:
foreach ($array1 as $key => $val) {
$array1[$key][] = $array3[$key];
$array1[$key][] = $array2[$key];
}
print_r($array1);
答案 1 :(得分:0)
array_merge函数怎么样?
答案 2 :(得分:0)
$merged = array();
foreach (array($array1,$array2,$array3) as $array) {
foreach ($array as $key=>$value) {
if (!isset($merged[$key])) {
$merged[$key] = array();
}
$merged[$key] += $value;
}
}
print_r($merged);
答案 3 :(得分:0)
$combined=$array0 + $array1;
试一下