我正在尝试在Oracle中创建一个介于两个多对多表之间的关系/表,因此该表的主键是复合键,但这两个键都是外来的。
CREATE TABLE employee_licence_certificate(
emp_id NUMBER(4) REFERENCES employee(emp_id)
, licence_cert_code VARCHAR2(6) REFERENCES licence_certificate(licence_cert_code)
, date_earned DATE NOT NULL
)
PRIMARY KEY (emp_id, licence_cert_code))
我尝试过使用合成键的方法,但我似乎得到了以下错误,这让我想知道这是否可能?
Error starting at line 1 in command:
CREATE TABLE employee_licence_certificate(emp_id NUMBER(4) REFERENCES employee(emp_id)
, licence_cert_code VARCHAR2(6) REFERENCES licence_certificate(licence_cert_code)
, date_earned DATE NOT NULL) PRIMARY KEY (emp_id, licence_cert_code))
Error at Command Line:3 Column:29
Error report:
SQL Error: ORA-00922: missing or invalid option
00922. 00000 - "missing or invalid option"
*Cause:
*Action:
答案 0 :(得分:4)
试试这个:
CREATE TABLE employee_licence_certificate(
emp_id NUMBER(4) REFERENCES employee(emp_id)
, licence_cert_code VARCHAR2(6) REFERENCES licence_certificate(licence_cert_code)
, date_earned DATE NOT NULL
,
PRIMARY KEY (emp_id, licence_cert_code))
答案 1 :(得分:4)
我使用不同的语法。我更喜欢明确地命名我的外键约束,以便错误消息if / when违反时更有意义/可追踪。所以我会这样做:
CREATE TABLE employee_licence_certificate
( emp_id NUMBER(4) NOT NULL
, licence_cert_code VARCHAR2(6) NOT NULL
, date_earned DATE NOT NULL
, CONSTRAINT elc_pk PRIMARY KEY (emp_id, licence_cert_code)
, CONSTRAINT elc_emp_fk FOREIGN KEY (emp_id)
REFERENCES employee(emp_id)
, CONSTRAINT elc_lct_fk FOREIGN KEY (licence_cert_code )
REFERENCES licence_certificate(licence_cert_code)
)
答案 2 :(得分:2)
确定有可能。你只需要修改你的陈述:
CREATE TABLE employee_licence_certificate(emp_id NUMBER(4) REFERENCES employee(emp_id)
, licence_cert_code VARCHAR2(6) REFERENCES licence_certificate(licence_cert_code)
, date_earned DATE NOT NULL, PRIMARY KEY (emp_id, licence_cert_code))
顺便说一下,在正确格式化语句时,更容易发现这些错误:
create table employee_licence_certificate
(
emp_id number(15) references employee(emp_id),
licence_cert_code VARCHAR2(6) REFERENCES licence_certificate(licence_cert_code),
date_earned date not null,
primary key (emp_id, licence_cert_code)
)