如何在ListBox中添加列表?

时间:2009-05-09 07:48:45

标签: c# .net asp.net

再次问好;我需要在ListBoxes中显示X,Y,Risk。但我不能这样做。

public partial class _Default : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        if (!IsPostBack)
        {
            List<TrainigSet> listtraining = new List<TrainigSet>();
            TrainigSet tr = new TrainigSet();
            double[] X = { 2, 3, 3, 4, 5, 6, 7, 9, 11, 10 };
            double[] Y = { 4, 6, 4, 10, 8, 3, 9, 7, 7, 2 };
            string[] Risk = { "Kötü", "iyi", "iyi", "kötü", "kötü", "iyi", "iyi", "kötü", "kötü", "kötü" };
            for (int i = 0; i < X.Length; i++)
            {
                tr.X = X[i];
                tr.Y = Y[i];
                tr.Risk = Risk[i];
                listtraining.Add(tr);
            }
            for (int i = 0; i < listtraining.Count; i++)
            {
                ListBox1.Items.Add(listtraining[i].X.ToString());
                ListBox2.Items.Add(listtraining[i].Y.ToString());
                ListBox3.Items.Add(listtraining[i].Risk.ToString());
            }
        }
    }
}

public class TrainigSet
{
    public double X { get; set; }
    public double Y { get; set; }
    public string Risk { get; set; }
}

2 个答案:

答案 0 :(得分:1)

您必须将TrainingSet的实例化/创建移动到for循环中(您希望为添加到listtraining的每个项目创建一个新实例):

double[] X = { ... };
double[] Y = { ... };
string[] Risk = { ... };

for (int i = 0; i > X.Length; i++)
{
    TrainigSet tr = new TrainigSet(); // create a new TrainingSet
    ...
    listtraining.Add(tr);
}

否则,您将一遍又一遍地修改相同的TrainingSet实例。

答案 1 :(得分:1)

您也可以使用具有公共X,Y和风险的TrainingResult类

public class TrainingResult
{
   public double X{get;set;}
   public double Y{get;set;}
   public string Risk {get;set};
}

并创建一个列表。接下来你可以像这样绑定它:

ListBoxX.DataSource = List<TrainingResult>
ListBoxX.DataMember = "X";
ListBoxX.DataBind();

ListBoxX.DataSource = List<TrainingResult>
ListBoxY.DataMember = "Y";
ListBoxY.DataBind();

ListBoxRisk.DataSource = List<TrainingResult>
ListBoxRisk.DataMember = "Risk";
ListBoxRisk.DataBind();

这样做的好处是,您可以在x,y和风险之间建立更清晰的关系,并获得更具可读性(对我而言)的代码。缺点是当然DataMember是一个字符串值。