Question

我有两个代理集。是否有寻找功能：

两个（交叉点）
存在于一个而非另一个

我发现手动实现这一点非常困难，特别是在三重ask

理想用法与with语法类似：

let cross set1 and-in set2
let uniq set1 with [color = red] not-in set2

简单的事情，例如“代理集X中的代理A？”是有问题的

Answer 1

对于第一个，您使用turtle-set原语。对于第二个，您需要member?原语，它也适用于代理集。就这样：

to setup
  ca
  create-turtles 10 [set color red]
  create-turtles 10 [set color blue]
  let red-ones turtles with [color = red]
  let blue-ones turtles with [color = blue]

  ;join 2 agent sets
  let joinset (turtle-set red-ones blue-ones)
  show joinset

  let even-ones (turtles with [who mod 2 = 0])
  ;subtract even-ones from red-ones
  let subtractset red-ones with [not member? self even-ones]
  show subtractset
end

NetLogo两个agentsets操作

1 个答案: