如果我运行启用了ipython %pdb
魔法的代码并且代码抛出异常,有没有办法告诉代码继续执行?
ValueError: x=0 not allowed
。我可以在pdb中设置x=1
并允许代码继续(恢复)执行吗?
答案 0 :(得分:5)
我认为你不能在事后恢复代码(即实际引发异常,触发调试器的调用)。您可以做什么,在您看到错误的代码中放置断点,并允许您更改值,并继续程序以避免错误。
给定一个脚本myscript.py
:
# myscript.py
from IPython.core.debugger import Tracer
# a callable to invoke the IPython debugger. debug_here() is like pdb.set_trace()
debug_here = Tracer()
def test():
counter = 0
while True:
counter += 1
if counter % 4 == 0:
# invoke debugger here, so we can prevent the forbidden condition
debug_here()
if counter % 4 == 0:
raise ValueError("forbidden counter: %s" % counter)
print counter
test()
它会不断递增计数器,如果它可以被4整除则会产生错误。但是我们已经编辑它以在错误条件下进入调试器,所以我们可以自救。
从IPython运行此脚本:
In [5]: run myscript
1
2
3
> /Users/minrk/dev/ip/mine/myscript.py(14)test()
13 debug_here()
---> 14 if counter % 4 == 0:
15 raise ValueError("forbidden counter: %s" % counter)
# increment counter to prevent the error from raising:
ipdb> counter += 1
# continue the program:
ipdb> continue
5
6
7
> /Users/minrk/dev/ip/mine/myscript.py(13)test()
12 # invoke debugger here, so we can prevent the forbidden condition
---> 13 debug_here()
14 if counter % 4 == 0:
# if we just let it continue, the error will raise
ipdb> continue
---------------------------------------------------------------------------
ValueError Traceback (most recent call last)
IPython/utils/py3compat.pyc in execfile(fname, *where)
173 else:
174 filename = fname
--> 175 __builtin__.execfile(filename, *where)
myscript.py in <module>()
17 print counter
18
---> 19 test()
myscript.py in test()
11 if counter % 4 == 0:
12 # invoke debugger here, so we can prevent the forbidden condition
13 debug_here()
14 if counter % 4 == 0:
---> 15 raise ValueError("forbidden counter: %s" % counter)
ValueError: forbidden counter: 8
In [6]: