Question

我使用UI.xml创建了fileupload小部件。书面Servlet。我的servlet正在调用但没有文件内容正在检索。我在这里粘贴了我的代码。你能否回答一下问题是什么以及如何检索内容？这是第一次使用它。请告诉我。

UI

<g:FormPanel ui:field="uploadDPAFormPanel">

        <g:HorizontalPanel>
            <g:Label> File
                Upload: &nbsp;&nbsp;&nbsp;</g:Label>
            <g:FileUpload ui:field="fileUpload" />

            <g:Button ui:field="uploadButton" title="Upload"
                Upload</g:Button>
        </g:HorizontalPanel>

</g:FormPanel>

以下是我的实施课程：

@UiHandler("uploadButton")
void onClickUploadButton(ClickEvent event) {
    GWT.log("You selected: " + fileUpload.getFilename(), null);
    uploadDPAFormPanel.submit();
}
public void init() {
    uploadDPAFormPanel.setEncoding(FormPanel.ENCODING_MULTIPART);
    uploadDPAFormPanel.setMethod(FormPanel.METHOD_POST);
    uploadDPAFormPanel.setAction(GWT.getHostPageBaseURL()
            + uploadServlet);
    uploadDPAFormPanel.addSubmitHandler(new FormPanel.SubmitHandler() {

        @Override
        public void onSubmit(SubmitEvent event) {

             if (!"".equalsIgnoreCase(fileUpload.getFilename())) { 
                 GWT.log("UPLOADING FILE????", null);   
                 // NOW WHAT???? 
                 }  
             else{  
                 GWT.log("UPLOA event cancel");
                 event.cancel(); // cancel the event  
                 } 
             } 
         }); 

    uploadDPAFormPanel
    .addSubmitCompleteHandler(new FormPanel.SubmitCompleteHandler() {
        @Override
        public void onSubmitComplete(SubmitCompleteEvent event) {
            //TODO need to write code to refresh the page
            doAlert("Uploaded sucessfully");
        }
    });
}

以下是我的servlet类：

public void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        ServletFileUpload upload = new ServletFileUpload();
        log.debug("UploadServlet upload:"+upload);
        try {


        FileItemIterator iter = upload.getItemIterator(request);
        log.debug("UploadServlet iter:"+iter);
        System.out.println("UploadServlet iter:"+iter);
        while (iter.hasNext()) {

            FileItemStream item = iter.next();
            log.debug("UploadServlet iter:Field Name:"+item.getFieldName());
            System.out.println(":Field Name:"+item.getFieldName());
            System.out.println(":Name:"+item.getName());
            System.out.println(":is form field:"+item.isFormField());
            String name = item.getFieldName();
            InputStream stream = item.openStream();
            // Process the input stream
            ByteArrayOutputStream out = new ByteArrayOutputStream();
            int len;
            byte[] buffer = new byte[8192];
            while ((len = stream.read(buffer, 0, buffer.length)) != -1) {
                out.write(buffer, 0, len);
            }
            int maxFileSize = 10 * (1024 * 2); // 10 megs max
            if (out.size() > maxFileSize) {
                throw new RuntimeException("File is > than " + maxFileSize);
            }
        }
    } catch (Exception e) {
        throw new RuntimeException(e);
    }
}

Answer 1

您应在name="..."上设置FileUpload。

在GWT中使用UI的FileUpload。调用Servlet但没有文件内容正在检索

1 个答案: