我有以下查询,它在2011年的StackOverflow上每天返回android个问题的数量。我想得到2011年所有问题的总和。为此,我是使用ROLLUP
。
select
year(p.CreationDate) as [Year],
month(p.CreationDate) as [Month],
day(p.CreationDate) as [Day],
count(*) as [QuestionsAskedToday]
from Posts p
inner join PostTags pt on p.id = pt.postid
inner join Tags t on t.id = pt.tagid
where
t.tagname = 'android' and
p.CreationDate > '2011-01-01 00:00:00'
group by year(p.CreationDate), month(p.CreationDate),day(p.CreationDate)
with rollup
order by year(p.CreationDate), month(p.CreationDate) desc,day(p.CreationDate) desc
这是输出:
2011年每天提出的所有问题的总和显示在QuestionsAskedToday列中。
有没有办法在带有别名的新列中显示汇总?
答案 0 :(得分:2)
要将其显示为列而不是行,您可以使用SUM(COUNT(*)) OVER ()
代替ROLLUP
。 (Online Demo)
SELECT YEAR(p.CreationDate) AS [Year],
MONTH(p.CreationDate) AS [Month],
DAY(p.CreationDate) AS [Day],
COUNT(*) AS [QuestionsAskedToday],
SUM(COUNT(*)) OVER () AS [Total]
FROM Posts p
INNER JOIN PostTags pt
ON p.id = pt.postid
INNER JOIN Tags t
ON t.id = pt.tagid
WHERE t.tagname = 'android'
AND p.CreationDate > '2011-01-01 00:00:00'
GROUP BY YEAR(p.CreationDate),
MONTH(p.CreationDate),
DAY(p.CreationDate)
ORDER BY YEAR(p.CreationDate),
MONTH(p.CreationDate) DESC,
DAY(p.CreationDate) DESC
答案 1 :(得分:1)
你可以采取这样的方法:Example
SELECT
YEAR(p.CreationDate) AS 'Year'
, CASE
WHEN GROUPING(MONTH(p.CreationDate)) = 0
THEN CAST(MONTH(p.CreationDate) AS VARCHAR(2))
ELSE 'Totals:'
END AS 'Month'
, CASE
WHEN GROUPING(DAY(p.CreationDate)) = 0
THEN CAST(DAY(p.CreationDate) AS VARCHAR(2))
ELSE 'Totals:'
END AS [DAY]
, CASE
WHEN GROUPING(MONTH(p.CreationDate)) = 0
AND GROUPING(DAY(p.CreationDate)) = 0
THEN COUNT(1)
END AS 'QuestionsAskedToday'
, CASE
WHEN GROUPING(MONTH(p.CreationDate)) = 1
OR GROUPING(DAY(p.CreationDate)) = 1
THEN COUNT(1)
END AS 'Totals'
FROM Posts AS p
INNER JOIN PostTags AS pt ON p.id = pt.postid
INNER JOIN Tags AS t ON t.id = pt.tagid
WHERE t.tagname = 'android'
AND p.CreationDate >= '2011-01-01'
GROUP BY ROLLUP(YEAR(p.CreationDate)
, MONTH(p.CreationDate)
, DAY(p.CreationDate))
ORDER BY YEAR(p.CreationDate)
, MONTH(p.CreationDate) DESC
, DAY(p.CreationDate) DESC
如果这是你想要的,那么同样的技术也可以应用于Years
以及在新列或它们自己的列中总计它们,如果你想查询多年并聚合它们。 / p>