Question

我有一个返回JSON的REST服务。但是JSON响应在引号（转义字符）之前返回\ _我需要删除那些escapre斜杠！

这是一个示例响应，显示正在发生的事情：

“[{\”Id \“：\”0 \“，\”FirstName \“：\”0firstname \“，\”LastName \“：\”0 lastname \“}，{\”Id \“ ：\“1 \”，\“FirstName \”：\“1firstname \”，\“LastName \”：\“1 lastname \”}，{\“Id \”：\“2 \”，\“FirstName \ “：\”2firstname \“，\”LastName \“：\”2 lastname \“}，{\”Id \“：\”3 \“，\”FirstName \“：\”3firstname \“，\”LastName \“：\”3 lastname \“}，{\”Id \“：\”4 \“，\”FirstName \“：\”4firstname \“，\”LastName \“：\”4 lastname \“}， {\“Id \”：\“5 \”，\“FirstName \”：\“5firstname \”，\“LastName \”：\“5 lastname \”}，{\“Id \”：\“6 \ “，”FirstName \“：\”6firstname \“，\”LastName \“：\”6 lastname \“}，{\”Id \“：\”7 \“，\”FirstName \“：\”7firstname \“，\”LastName \“：\”7 lastname \“}，{\”Id \“：\”8 \“，\”FirstName \“：\”8firstname \“，\”LastName \“：\” 8 lastname \“}，{\”Id \“：\”9 \“，\”FirstName \“：\”9firstname \“，\”LastName \“：\”9 lastname \“}，{\”Id \ “：\”10 \“，\”FirstName \“：\”10firstname \“，\”LastName \“：\”10 lastname \“}]”

JAR由Layar解析（http://layar.pbworks.com/w/page/28473583/GetPOIs-Request%20and%20Response%20Examples），所以我不能影响解析，他们不允许这些转义字符

这是我的代码：

** RestServiceImpl.vb

Imports System.ServiceModel
Imports System.ServiceModel.Web
Imports System.IO
Imports System.ServiceModel.Activation
Imports System.Web.Script.Serialization
Imports System.Collections.Generic

Namespace RestService

Public Class Employee
    Public Property Id() As String
        Get
            Return m_Id
        End Get
        Set(value As String)
            m_Id = Value
        End Set
    End Property
    Private m_Id As String
    Public Property FirstName() As String
        Get
            Return m_FirstName
        End Get
        Set(value As String)
            m_FirstName = Value
        End Set
    End Property
    Private m_FirstName As String
    Public Property LastName() As String
        Get
            Return m_LastName
        End Get
        Set(value As String)
            m_LastName = Value
        End Set
    End Property
    Private m_LastName As String
End Class

<AspNetCompatibilityRequirements(RequirementsMode:=AspNetCompatibilityRequirementsMode.Allowed)> _
Public Class RestServiceImpl
    Implements IRestServiceImpl

    Public Function XMLData(ByVal id As String) As String _
        Implements IRestServiceImpl.XMLData

        Return "XML You requested product " & id

    End Function

    Public Function JSONData(ByVal lat As String, ByVal lng As String, ByVal d As String, ByVal cat As String) As String _
        Implements IRestServiceImpl.JSONData

        Dim json As New JavaScriptSerializer()
        Dim l As New List(Of Employee)

        Dim e As Employee
        For i As Integer = 0 To 10
            e = New Employee
            e.Id = i.ToString
            e.FirstName = i.ToString + "firstname"
            e.LastName = i.ToString + " lastname"
            l.Add(e)
        Next i

        Dim jsonMessage As String = json.Serialize(l.ToArray())
        Return jsonMessage

    End Function

End Class



End Namespace

** IRestServiceImpl.vb

Imports System.ServiceModel
Imports System.ServiceModel.Web
Imports System.IO
Imports System.ServiceModel.Activation

Namespace RestService
' NOTE: You can use the "Rename" command on the context menu to change the interface name "IRestServiceImpl" in both code and config file together.
<ServiceContract()> _
Public Interface IRestServiceImpl
    <OperationContract()> _
    <WebInvoke(Method:="GET", ResponseFormat:=WebMessageFormat.Xml, BodyStyle:=WebMessageBodyStyle.Wrapped, UriTemplate:="xml/{id}")> _
    Function XMLData(ByVal id As String) As String


    'WebMessageBodyStyle.Bare WAS WebMessageBodyStyle.wrapped
    <OperationContract()> _
    <WebInvoke(Method:="GET", ResponseFormat:=WebMessageFormat.Json, BodyStyle:=WebMessageBodyStyle.Bare, UriTemplate:="api/objects/json/?lat={lat}&lon={lon}&radius={radius}&cat={cat}")> _
    Function JSONData(ByVal lat As String, ByVal lon As String, ByVal radius As String, ByVal cat As String) As String
    'radius in meters
End Interface


Public Class RawService
    <OperationContract(), WebGet()> _
    Public Function GetValue() As System.IO.Stream
        Dim result As String = "Hello world"
        Dim resultBytes As Byte() = Encoding.UTF8.GetBytes(result)
        WebOperationContext.Current.OutgoingResponse.ContentType = "text/plain"
        Return New MemoryStream(resultBytes)
    End Function

End Class

End Namespace

Answer 1

原来如此手动序列化json是不好的：json.Serialize（l.ToArray（））。我在这里读到这个：http://encosia.com/asp-net-web-services-mistake-manual-json-serialization/ 所以，我所做的只是返回员工名单，现在一切都很好！

Answer 2

这些斜杠是引号的转义字符，它正确地执行，因为返回类型是String。您可以更改您的JSONData以返回As List（Of Employee）...

Public Function JSONData(ByVal lat As String, ByVal lng As String, ByVal d As String, ByVal cat As String) As List(Of Employee) _
            Implements IRestServiceImpl.JSONData

            Dim json As New JavaScriptSerializer()
            Dim l As New List(Of Employee)

            Dim e As Employee
            For i As Integer = 0 To 10
                e = New Employee
                e.Id = i.ToString
                e.FirstName = i.ToString + "firstname"
                e.LastName = i.ToString + " lastname"
                l.Add(e)
            Next i


            Return json.Serialize(l.ToArray())

End Function

引号前返回的JSON响应为什么？为什么？

2 个答案: