我正在使用swfupload
插件。当我尝试上传图像时,我想传递两个参数,但参数没有被传递。
var id1='g';
var opt1='g';
function getValues()
{
id1 = $("#id").val();
opt1=$("#opt").val();
return id1.concat(opt1);
}
$(document).ready(function(){
alert(getValues()); // Here coming
$('#swfupload-control').swfupload({
upload_url: "upload-file.php?para=getValues()",//Here not coming
file_post_name: 'uploadfile',
file_size_limit : "8024",
file_types : "*.jpg;*.png;*.gif",
file_types_description : "Image files",
file_upload_limit : 10,
flash_url : "js/swfupload/swfupload.swf",
button_image_url : 'js/swfupload/wdp_buttons_upload_114x29.png',
button_width : 114,
button_height : 29,
button_placeholder : $('#button')[0],
debug: false
})
.bind('fileQueued', function(event, file){
var listitem='<li id="'+file.id+'" >'+
'File: <em>'+file.name+'</em> ('+Math.round(file.size/1024)+' KB) <span class="progressvalue" ></span>'+
'<div class="progressbar" ><div class="progress" ></div></div>'+
'<p class="status" >Pending</p>'+
'<span class="cancel" > </span>'+
'</li>';
$('#log').append(listitem);
$('li#'+file.id+' .cancel').bind('click', function(){
var swfu = $.swfupload.getInstance('#swfupload-control');
swfu.cancelUpload(file.id);
$('li#'+file.id).slideUp('fast');
});
// start the upload since it's queued
$(this).swfupload('startUpload');
})
.bind('fileQueueError', function(event, file, errorCode, message){
alert('Size of the file '+file.name+' is greater than limit');
})
.bind('fileDialogComplete', function(event, numFilesSelected, numFilesQueued){
$('#queuestatus').text('Files Selected: '+numFilesSelected+' / Queued Files: '+numFilesQueued);
})
.bind('uploadStart', function(event, file){
$('#log li#'+file.id).find('p.status').text('Uploading...');
$('#log li#'+file.id).find('span.progressvalue').text('0%');
$('#log li#'+file.id).find('span.cancel').hide();
})
.bind('uploadProgress', function(event, file, bytesLoaded){
//Show Progress
var percentage=Math.round((bytesLoaded/file.size)*100);
$('#log li#'+file.id).find('div.progress').css('width', percentage+'%');
$('#log li#'+file.id).find('span.progressvalue').text(percentage+'%');
})
.bind('uploadSuccess', function(event, file, serverData){
var item=$('#log li#'+file.id);
item.find('div.progress').css('width', '100%');
item.find('span.progressvalue').text('100%');
var pathtofile='<a href="uploads/'+file.name+'" target="_blank" >view »</a>';
item.addClass('success').find('p.status').html('Done!!! | '+pathtofile);
})
.bind('uploadComplete', function(event, file){
// upload has completed, try the next one in the queue
$(this).swfupload('startUpload');
})
});
});
</script>
答案 0 :(得分:5)
你有一个字符串函数调用。你需要打破字符串并将函数的结果连接到字符串上。
upload_url: "upload-file.php?para=getValues()"
变为:
upload_url: "upload-file.php?para=" + getValues()
答案 1 :(得分:2)
具有以下代码的行不会调用函数getValues(),因为它只是一个字符串。
upload_url: "upload-file.php?para=getValues()",
我假设您要调用该函数,而不是在网址中输入“getValues()”,对吗?