Question

-(id) initWithData:(NSString *)lastName: (NSString *)firstName{
self->firstname =  firstName;
self->lastname =  lastName;

return self;
}


-(void) printData {
NSLog(@"firstname: %@", firstname);
NSLog(@"lastname: %@", lastname);
}

所以每当我使用上面的init函数创建一个新对象时。并使用addObject函数将对象添加到NSMutableArray。

NSMutableArray *objectArray = [[NSMutableArray alloc] init];

CustomObject *tempObject = [[CustomObject alloc] initWithData: @"smith": @"john"];
CustomObject *tempObjectb = [[CustomObject alloc] initWithData: @"brown": @"william"];
[objectArray addObject:tempObject];
[objectArray addObject:tempObjectb];

[[objectArray objectAtIndex:0] printData];
[[objectArray objectAtIndex:1] printData];

索引为1的对象，0总是等于最后添加到数组中的对象如果我使用for循环，或者有两个以上的对象，打印时的所有值，转到objectArray的最后添加对象的值，也会发生这种情况。如果有任何我遗漏的信息，请告诉我。有什么东西我错过了吗？

Answer 1

修复您的initWithData:lastName:实施，如下所示：

-(id) initWithData:(NSString *)lastName: (NSString *)firstName
{

self = [super init];
if ( nil != self ) {
  self->firstname =  [firstName retain];
  self->lastname =  [lastName retain];
}

return self;
}

将自定义对象添加到NSMutableArray会覆盖整个数组

1 个答案: