Spring-JPA在readOnly事务之后不会导致insert?

时间:2011-12-06 19:10:38

标签: spring jpa transactions annotations readonly

在事务ReadOnly!

之后,不会执行持久化/插入过程

我的applicationContext.xml:

<bean id="transactionManagerConstant" class="org.springframework.orm.jpa.JpaTransactionManager">
    <property name="entityManagerFactory" ref="constant"/>
    <property name="jpaDialect" ref="jpaDialect" />
</bean>

<bean id="constant" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
    <property name="persistenceUnitManager" ref="persistenceUnitManager" />
    <property name="persistenceUnitName" value="JSFSpring" />
</bean>

Java代码:

@Transactional(isolation = Isolation.SERIALIZABLE, propagation = Propagation.REQUIRED, readOnly=false)
public String workSaved(){
    em.persist(work);
    work = (Work) ctx.getBean("work");
    return "/list.xhtml";
}

@Transactional(propagation = Propagation.REQUIRED, readOnly=true)
public List<Odev> getWorkedList() {
    return workedList = (List<Work>) em.createNamedQuery("Work.findAll").getResultList();
}

异常: javax.persistence.PersistenceException:org.hibernate.exception.GenericJDBCException:无法插入:[com.hakdogan.hakdoganjsfspring.entity.Work]

引起:java.sql.SQLException:连接是只读的。不允许导致数据修改的查询     在com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1073)     在com.mysql.jdbc.SQLError.createSQLException(SQLError.java:987)     在com.mysql.jdbc.SQLError.createSQLException(SQLError.java:982)     在com.mysql.jdbc.SQLError.createSQLException(SQLError.java:927)     在com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2378)     在com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2345)     在com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2330)     at org.hibernate.id.IdentityGenerator $ GetGeneratedKeysDelegate.executeAndExtract(IdentityGenerator.java:94)     at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:57)     ......还有73个

0 个答案:

没有答案