是否可以对公用表表达式执行JOIN子查询?如果没有,那么有人可以让我知道如何执行我在下面尝试做的事情吗?例子很棒。
例如:
LEFT JOIN (
;WITH [UserDefined]
AS (SELECT *, -- Make sure we get only the latest revision.
ROW_NUMBER() OVER (PARTITION BY [ID]
ORDER BY [RevisionNumber] DESC) AS RN
FROM [syn_Change])
SELECT [UserDefined].[ID]
,[UserDefined].[ChangeNumber]
,[UserDefined].[Usr_CoResponsibility]
,[UserDefined].[Usr_StarFlowStatus]
FROM [UserDefined]
WHERE (RN = 1)
) [UserColumns]
ON [UserColumns].[ChangeNumber] = [CTE].[ChangeNumber]
以下是我的完整查询:
;WITH CTE
AS (SELECT *, -- Make sure we get only the latest revision.
ROW_NUMBER() OVER (PARTITION BY [ItemID]
ORDER BY [RevisionNumber] DESC) AS RN
FROM [dw_Change])
SELECT [CTE].[ItemID]
,[CTE].[ViewID]
,[CTE].[FolderItemID]
,[CTE].[RevisionNumber]
,[CTE].[ChangeNumber]
,[CTE].[Synopsis]
,[CTE].[Description]
,[CTE].[EnteredOn]
,[CTE].[Responsibility]
--,[UserColumns].[Usr_CoResponsibility]
--,[UserColumns].[Usr_StarFlowStatus]
,[CTE].[Status] -- This will display the human name on the front-end with code.
,[Users].[F7] AS [ResponsibilityName]
,[GroupName].[Name] AS [AppGroupName]
,[AppName].[Name] AS [AppName]
FROM CTE
LEFT JOIN [S3] [Users] ON [Users].[F0] = [CTE].[Responsibility]
LEFT JOIN (SELECT [Name], [ViewID]
FROM [dw_Folder]
WHERE ([FolderItemID] = -1)) [GroupName]
ON [GroupName].[ViewID] = [CTE].[ViewID]
LEFT JOIN (SELECT [Name], [ItemID]
FROM [dw_Folder]
WHERE ([FolderItemID] <> -1)) [AppName]
ON [AppName].[ItemID] = [CTE].[FolderItemID]
LEFT JOIN (
;WITH [UserDefined]
AS (SELECT *, -- Make sure we get only the latest revision.
ROW_NUMBER() OVER (PARTITION BY [ID]
ORDER BY [RevisionNumber] DESC) AS RN
FROM [syn_Change])
SELECT [UserDefined].[ID]
,[UserDefined].[ChangeNumber]
,[UserDefined].[Usr_CoResponsibility]
,[UserDefined].[Usr_StarFlowStatus]
FROM [UserDefined]
WHERE (RN = 1)
) [UserColumns]
ON [UserColumns].[ChangeNumber] = [CTE].[ChangeNumber]
WHERE (RN = 1)
非常感谢!
答案 0 :(得分:39)
在定义CTE时,您在查询的其余任何内容之前执行此操作。所以你不能写:
LEFT JOIN (
;WITH CTE
...
)
快速地,原因人们将;
放在WITH
前面是因为所有先前的陈述都需要终止。如果开发人员习惯于使用;
终止所有SQL语句,那么就没有必要,但我离题了......
您可以像这样编写多个CTE:
WITH SomeCTE AS (
SELECT ...
FROM ...
), AnotherCTE AS (
SELECT ...
FROM ...
)
SELECT *
FROM SomeCTE LEFT JOIN
AnotherCTE ON ...
;
答案 1 :(得分:3)
如果你有多个CTE,他们需要在你的陈述的开头(以逗号分隔,只有一个;WITH
来开始CTE列表):
;WITH CTE AS (......),
[UserDefined] AS (.......)
SELECT.....
然后您可以在SELECT
语句中使用两者(甚至两个以上)。
答案 2 :(得分:3)
需要首先声明多个CTE。例如:
WITH CTE_1 AS
(
....
),
CTE_2 AS
(
...
)
SELECT *
FROM FOO
LEFT JOIN CTE_1
LEFT JOIN CTE_2
答案 3 :(得分:1)
答案 4 :(得分:1)
;
WITH
RANKED_CTE AS
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY [ItemID] ORDER BY [RevisionNumber] DESC) AS RN
FROM
[dw_Change]
)
,
CTE AS
(
SELECT
*
FROM
RANKED_CTE
WHERE
RN = 1
)
,
GroupName AS
(
SELECT
[Name], [ViewID]
FROM
[dw_Folder]
WHERE
([FolderItemID] = -1)
)
,
AppName AS
(
SELECT
[Name], [ItemID]
FROM
[dw_Folder]
WHERE
([FolderItemID] <> -1)
)
SELECT [CTE].[ItemID]
,[CTE].[ViewID]
,[CTE].[FolderItemID]
,[CTE].[RevisionNumber]
,[CTE].[ChangeNumber]
,[CTE].[Synopsis]
,[CTE].[Description]
,[CTE].[EnteredOn]
,[CTE].[Responsibility]
--,[UserColumns].[Usr_CoResponsibility]
--,[UserColumns].[Usr_StarFlowStatus]
,[CTE].[Status] -- This will display the human name on the front-end with code.
,[Users].[F7] AS [ResponsibilityName]
,[GroupName].[Name] AS [AppGroupName]
,[AppName].[Name] AS [AppName]
FROM
CTE
LEFT JOIN [S3] [Users] ON [Users].[F0] = [CTE].[Responsibility]
LEFT JOIN [GroupName] ON [GroupName].[ViewID] = [CTE].[ViewID]
LEFT JOIN [AppName] ON [AppName].[ItemID] = [CTE].[FolderItemID]