Question

我有以下字符串：

HTTP/1.1 200 OK
Date: Tue, 06 Dec 2011 11:53:22 GMT
Server: Apache/2.2.14 (Ubuntu)
X-Powered-By: PHP/5.3.2-1ubuntu4.9
Vary: Accept-Encoding
Content-Encoding: gzip
Content-Length: 48
Content-Type: text/html

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                          �4�@��AQ������t

我想提取到"\r\n\r\n"，丢弃二进制数据。即：

HTTP/1.1 200 OK
Date: Tue, 06 Dec 2011 11:53:22 GMT
Server: Apache/2.2.14 (Ubuntu)
X-Powered-By: PHP/5.3.2-1ubuntu4.9
Vary: Accept-Encoding
Content-Encoding: gzip
Content-Length: 48
Content-Type: text/html

如何在C中执行此操作？

Answer 1

这可以通过简单地找到前两个连续的换行符来轻松完成，因为这会终止标头，然后将所有内容复制到一个单独的缓冲区：

// find the end of the header, which is terminated
// by two linebreaks
char* end = strstr(header, "\r\n\r\n");
char* buffer = 0;
if(end) {
    // allocate memory to hold the entire header
    buffer = malloc((end - header) + 1);
    if(buffer) {
        // copy header to buffer
        memcpy(buffer, header, end - header);
        // null terminate the buffer
        buffer[end - header] = 0;
        // do something with the buffer

        // don't forget to release the allocated memory
        free(buffer);
    }
}

Answer 2

您可以使用strstr功能。

但请注意，HTTP客户端（如libcurl）和HTTP服务器（如onion）端存在良好的C库。 HTTP的细节很复杂。

如何获得子串到“\ r \ n \ r \ n”

2 个答案: