如何转换以下字符串
09/11/2011 9:40:55 pm 20/11/2011 3:40:55 am
进入C#DateTime?
答案 0 :(得分:11)
string dateString = "20/11/2011 3:40:55 am";
DateTime parsedDate = DateTime.ParseExact(
dateString,
"dd/MM/yyyy h:mm:ss tt",
CultureInfo.InvariantCulture);
答案 1 :(得分:-1)
DateTime.Parse:
http://msdn.microsoft.com/en-us/library/1k1skd40.aspx
另见:
http://msdn.microsoft.com/en-us/library/system.globalization.datetimeformatinfo.timeseparator.aspx
http://msdn.microsoft.com/en-us/library/system.datetime.aspx
例如:
string dateString = "5/1/2008 8:30:52 AM";
DateTime date1 = DateTime.Parse(dateString,
System.Globalization.CultureInfo.InvariantCulture);
答案 2 :(得分:-2)
DateTime DT_1 = new DateTime(2011, 11, 9, 21, 40, 55);
DateTime DT_2 = new DateTime(2011, 11, 20, 15, 40, 55);