我正在为我的网站创建自动填充功能。 到目前为止,javascript部分已经结束了。此外,我可以获得匹配的用户的MembershipUser对象。
我需要以下列格式返回JSON:
{
query:'Li',
suggestions:['Liberia','Libyan Arab Jamahiriya','Liechtenstein','Lithuania'],
data:['LR','LY','LI','LT']
}
这是ashx中的代码:
public void ProcessRequest (HttpContext context) {
System.Web.Script.Serialization.JavaScriptSerializer JsonSerializer;
string query = context.Request.QueryString["query"];
System.Web.Security.MembershipUserCollection Users = System.Web.Security.Membership.GetAllUsers();
context.Response.ContentType = "application/json";
foreach (System.Web.Security.MembershipUser User in Users)
{
if (User.UserName.StartsWith(query.ToLower()))
{
context.Response.Write(query + Environment.NewLine);
context.Response.Write(User.Email);
}
}
}
如何以所需格式返回json? 感谢。
答案 0 :(得分:35)
context.Response.Write(
jsonSerializer.Serialize(
new
{
query = "Li",
suggestions = new[] { "Liberia", "Libyan Arab Jamahiriya", "Liechtenstein", "Lithuania" },
data = new[] { "LR", "LY", "LI", "LT" }
}
)
);
答案 1 :(得分:18)
这有助于我:
using System;
using System.Data;
using System.Web;
using System.Linq;
using System.Collections;
using Newtonsoft.Json;
public class Handler : IHttpHandler {
public void ProcessRequest (HttpContext context) {
context.Response.ContentType = "application/json";
string quer = context.Request["query"];
DataTable _t = AMC.Core.Logic.Root.Storage.ExecuteQuery("SELECT [tag_name] FROM [tags] Where [tag_name] like '%' + @ke + '%'", new System.Data.SqlClient.SqlParameter("ke", quer));
DataRow[] list = new DataRow[_t.Rows.Count];
_t.Rows.CopyTo(list, 0);
var wapper = new {
query = quer
, suggestions = (from row in list select row["tag_name"].ToString()).ToArray()
//, data = new[] { "LR", "LY", "LI", "LT" }
};
context.Response.Write(JsonConvert.SerializeObject(wapper));
}
Newtonsoft.Json将在此处找到:http://json.codeplex.com/releases/
答案 2 :(得分:5)
根据您想要的回报创建一个具有合同的类,然后在该类的实例上使用JSONSerializer来创建返回内容
[DataContract]
public class YourReturnObject {
[DataMember(Name="query")]
public String Query { get;set;}
[DataMember(Name="suggestions")]
public String[] Suggestions { get;set;}
[DataMember(Name="data")]
public String[] OtherData{ get;set;}
}
答案 3 :(得分:5)
你的json有点尴尬,因为你必须维护这两个数组的索引。我可以建议更像这样的东西吗?
{
query: 'Li',
data: [{id:'LR', text:'Liberia'}, {id:'LY', text:'Libyan Arab Jamahiriya'}, ...]
}