Question

基本上我要做的就是做一个刽子手游戏。虽然我在比赛中扭曲了。我想做的是有程序

因此，如果用户输入“a”作为第一次尝试，则游戏将在其中找到所有带有“a”的单词并将其从列表中删除等等，这意味着您几乎总是会错过前4个元音。最终你会让程序坚持一个单词，因为没有一个有效的单词可以切换到没有用户已经选择的字母。

我的问题是，如何才能将所有删除的单词放入已删除的列表中？

# HANGMAN
import random

def main():
    num_wrong=0
    word_list=['car', 'road', 'truck', 'dog', 'desk', 'tree', \
               'cat', 'zug', 'acu', 'python']
    left=['a','b','c','d','e','f','g','h','i','j','k','l',\
          'm','n','o','p','q','r','s','t','u','v','w','x',\
          'y','z']
    let_guessed=[]
    let_unguessed=['a','b','c']

    finished=False
    r=random.randint(0,len(word_list)-1)
    answer=word_list[r]
    current='_'*len(answer)

    show_status(current,num_wrong,left)

    guess=input('Guess a letter: ')
    while num_wrong<6 and not finished: # after 6 you lose
        left.remove(guess)
        if guess not in answer:
            num_wrong+=1
            print(guess,'is not in the word')
        else: # if the guess is correct
            print(guess,'is in the word')
            # modify current

            for z in range(len(answer)):
                # check to see if we have an alphabetic at that spot already
                if answer[z]==guess:
                    current=current[0:z]+guess+current[z+1:]
                    if answer==current:
                        print('You win!')
                        finished=True

        show_status(current,num_wrong,left)
        if not finished:
            guess=input('Guess a letter: ')

def show_status(str1,x,letters):
    for a in str1:
        print(a+' ',end='')
    print('You have made',x,'wrong guesses so far.')
    print('The following letters are still available:')
    str1=''
    for each in letters:
        str1+=each+' '
    print(str1)

main()

Answer 1

只需创建一个没有用户选择的字母的新列表：

word_list = [w for w in word_list if chosen_letter not in w]

需要帮助从列表中删除到另一个列表

1 个答案: