Question

我一直坚持这个问题几个小时似乎无法解决，所以我在这里问：）

好吧，我有这个功能：

private void XmlDump()
{
    XDocument doc = new XDocument(new XDeclaration("1.0", "utf-8", "yes"));
    XElement rootElement = new XElement("dump");
    rootElement.Add(TableToX("Support"));

    string connectionString = ConfigurationManager.ConnectionStrings["MyDb"].ConnectionString;
    SqlConnection con = new SqlConnection(connectionString);
    string sql = "select * from support";
    SqlDataAdapter da = new SqlDataAdapter(sql, con);

    DataSet ds = new DataSet("Test");
    da.Fill(ds, "support");

    // Convert dataset to XML here

    var docresult = // Converted XML

    Response.Write(docResult);
    Response.ContentType = "text/xml; charset=utf-8";
    Response.AddHeader("Content-Disposition", "attachment; filename=test.xml");
    Response.End();
}

我一直在尝试各种不同的东西，但我一直在收到错误，所以我离开了如何将DataSet转换为XML部分空白。

另外，此查询包含具有特殊字符的列。

Answer 1

您可以使用ds.WriteXml，但这需要您输入Stream。如果您想要输出字符串，请尝试以下扩展方法：

public static class Extensions
{
    public static string ToXml(this DataSet ds)
    {
        using (var memoryStream = new MemoryStream())
        {
            using (TextWriter streamWriter = new StreamWriter(memoryStream))
            {
                var xmlSerializer = new XmlSerializer(typeof(DataSet));
                xmlSerializer.Serialize(streamWriter, ds);
                return Encoding.UTF8.GetString(memoryStream.ToArray());
            }
        }
    }
}

<强> USAGE：

var xmlString = ds.ToXml();
// OR
Response.Write(ds.ToXml());

Answer 2

只需使用Dataset.getXml()：

doc.LoadXml(ds.GetXml());

Answer 3

写下面的代码部分

DataTable dt = new DataTable("MyData");
dt.WriteXml(@Application.StartupPath + "\\DataBaseValues.xml");

或者，您也可以像Oded一样直接转换dataSet，

private void WriteXmlToFile(DataSet thisDataSet)
{
   if (thisDataSet == null) 
   {
      return;
   }

   // Create a file name to write to.
   string filename = "myXmlDoc.xml";

   // Create the FileStream to write with.
   System.IO.FileStream myFileStream = new System.IO.FileStream(filename, System.IO.FileMode.Create);

   // Create an XmlTextWriter with the fileStream.
   System.Xml.XmlTextWriter myXmlWriter = 
   new System.Xml.XmlTextWriter(myFileStream, System.Text.Encoding.Unicode);

   // Write to the file with the WriteXml method.
   thisDataSet.WriteXml(myXmlWriter);   
   myXmlWriter.Close();
}

Answer 4

使用DataSet.WriteXml - 它会将数据集输出为XML。

Answer 5

我们也可以使用

 
  Private Function DsToXML(DataSet ds) as System.Xml.XmlDataDocument

    Dim xmlDoc As System.Xml.XmlDataDocument 
    Dim xmlDec As System.Xml.XmlDeclaration
    Dim xmlWriter As System.Xml.XmlWriter
    xmlWriter = New XmlTextWriter(context.Response.OutputStream,System.Text.Encoding.UTF8)

    xmlDoc = New System.Xml.XmlDataDocument(ds)
    xmlDoc.DataSet.EnforceConstraints = False
    xmlDec = xmlDoc.CreateXmlDeclaration("1.0", "UTF-8", Nothing)
    xmlDoc.PrependChild(xmlDec)
    xmlDoc.WriteTo(xmlWriter)
    Retuen xmlDoc
  End Eunction

Answer 6

如果ds是您的数据集..

你可以使用：

ds.getXml();

这有助于获取XML

Answer 7

尝试一下。它对我有用。

static XmlDocument xdoc = new XmlDocument(); //static; since i had to access this file someother place too
protected void CreateXmlFile(DataSet ds) 
    {
      //ds contains sales details in this code; i.e list of products along with quantity and unit
      //You may change attribute acc to your needs ; i.e employee details in the below code

        string salemastid = lbl_salemastid.Text;
        int i = 0, j=0;
        String str = "salemastid:" + salemastid;
        DataTable dt = ds.Tables[0];
        string xml = "<Orders>" ;
         while (j < dt.Rows.Count)
         {
             int slno = j + 1;
             string sl = slno.ToString();
             xml += "<SlNo>" + sl +"</SlNo>" +
                       "<PdtName>" + dt.Rows[j][0].ToString() + "</PdtName>" +
                       "<Unit>" + dt.Rows[j][1].ToString() + "</Unit>" +
                       "<Qty>" + dt.Rows[j][2].ToString() + "</Qty>";
             j++;
         }
         xml += "</Orders>";

         xdoc.LoadXml(xml);
         //Here the xml is prepared and loaded in xml DOM.

         xdoc.Save(Server.MapPath("Newsales.xml"));
         //You may also use some other names instead of 'Newsales.xml'

         //to get a downloadable file use the below code
         System.IO.MemoryStream stream = new System.IO.MemoryStream();
                XmlTextWriter xwriter = new XmlTextWriter(stream, System.Text.Encoding.UTF8);

                xdoc.WriteTo(xwriter);
                xwriter.Flush();
                Response.Clear();
                Encoding.UTF8.GetString(stream.ToArray());
                byte[] byteArray = stream.ToArray();
                Response.AppendHeader("Content-Disposition", "filename=OrderRequest.xml");
                Response.AppendHeader("Content-Length", byteArray.Length.ToString());
                Response.ContentType = "application/octet-stream";
                Response.BinaryWrite(byteArray);
                xwriter.Close();
                stream.Close();

        }

将数据集转换为XML

7 个答案: