我应该如何加入这五张桌子呢？ SUM多个表中的多个列

Question

我有一个包含5个具有相关数据的表的数据库。 它看起来像这样..

表“associate_payin_ad”存储注册日期＆amp;附件id。实际上，附件只是一张纸，可以有零个或多个“Payin”或“Associate”条目。
'payin'＆amp; 'associate'表格有多种付款模式（如现金，支票，bdcash，bdcheque）[金额]＆amp; [付款]专栏.. bycash，bycheque，bybdcash＆amp; bybdcheque，我只展示了'bycash'表格。
如果表格中填写了以下给定的数据..

[associate_payin_ad] Table:  
adid | date_register | annexure_id  
1 | 05/12/2011 | 1  
2 | 05/12/2011 | 2  
3 | 06/12/2011 | 1  
4 | 07/12/2011 | 1  

[payin] Table:  
fid | amount | adid  
1 | 10000 | 1  [this entry was made on 05/12/2011 in annexure no 1]  
2 | 10000 | 1  [this entry was made on 05/12/2011 in annexure no 1]  
3 | 40000 | 2  [this entry was made on 05/12/2011 in annexure no 2]  
4 | 10000 | 4  [this entry was made on 07/12/2011 in annexure no 1]  

[payin_bycash] Table:  
fid | bycash  
1 |  10000  
2 |  10000  
3 |  40000  
4 |  10000  

[associate] table...  
 aid | payment | adid  
 1 | 200 | 1  [this entry was made on 05/12/2011 in annexure no 1]  
 2 | 200 | 3  [this entry was made on 06/12/2011 in annexure no 1]  

[associate_bycash] table...  
 aid | bycashajf  
 1 | 200  
 2 | 200  

我需要[payin_bycash.bycash]＆amp;的SUM。 [associate_bycash.bycashajf]针对特定日期范围..（例如，2011年12月12日至2011年12月7日）

date_register | amount  
05/12/2011 | 60200  
06/12/2011 | 200  
07/12/2011 | 10000  

我从昨天开始试图找出合适的查询，我一直在圈子里跑来跑去。我能想出的最好的就是这个，但是徒劳无功：

SELECT apad.date_register,  
SUM(ISNULL(pica.cash_in_hand, 0)) + SUM(ISNULL(aca.bycashajf, 0)) AS amount  
FROM associate_payin_ad AS apad LEFT OUTER JOIN  
payin AS pi ON apad.adid = pi.adid INNER JOIN  
payin_bycash AS pica ON pi.fid = pica.fid  
LEFT OUTER JOIN associate AS asso ON apad.adid = asso.adid INNER JOIN  
associate_bycash AS aca ON asso.aid = aca.aid  
WHERE (apad.date_register BETWEEN @date_initial AND @date_final)  
GROUP BY apad.date_register

上面的查询只返回我..

date_register | amount  
05/12/2011 | 20400  

我做错了什么？

提前thnx

Answer 1

你不能像这样混合内部和外部联接。当您使用左外连接时，它将在右侧表中返回空记录，以确保左手表中的所有行都按预期返回。但是，如果您尝试使用INNER连接将右侧表连接到另一个表，则将过滤掉空记录，因为在另一个表中不会有匹配的空记录。

在您的情况下，当您加入payin时会发生这种情况。你会得到一行援助= 3，但是当你尝试加入payin_bycash时，那一行被过滤掉了，因为payin中不存在aid = 3.你的联合关联也存在同样的问题。

解决此问题的最佳方法是将联接保留为子查询（或者您可以使用CRE执行此操作）。试试这个：

SELECT apad.date_register,  
SUM(ISNULL(pica.cash_in_hand, 0)) + SUM(ISNULL(aca.bycashajf, 0)) AS amount  
FROM associate_payin_ad AS apad 
LEFT OUTER JOIN 
(
  SELECT payin_bycash.cash_in_hand 
  FROM payin 
  INNER JOIN payin_bycash ON payin.fid = payin_bycash.fid  
) pi ON apad.adid = pi.adid 
LEFT OUTER JOIN 
(
  SELECT associate_bycash.bycashajf 
  FROM associate
  INNER JOIN associate_bycash ON associate.aid = associate_bycash.aid  
) asso ON apad.adid = asso.adid 
WHERE (apad.date_register BETWEEN @date_initial AND @date_final)  
GROUP BY apad.date_register

另外，请阅读：http://weblogs.sqlteam.com/jeffs/archive/2007/10/11/mixing-inner-outer-joins-sql.aspx