Question

如何从NSString中提取分钟和秒？例子：

3'15" or 3' 15" (3 minutes 15 seconds)
28" (28 seconds)
2' (2 minutes)
50 (default is in seconds, 50 seconds)

并存储到两个NSInteger s？

Answer 1

并不完全相信RegEx匹配是从字符串中读取数字的最佳方式，但这是一个有效的代码片段：

NSString *str = @"12'34\"";

NSString *minutePattern = @"[[:digit:]]+'";
NSString *secondPattern = @"[[:digit:]]+\"?";

NSRange minuteRange = [str rangeOfString: minutePattern options: NSRegularExpressionSearch];

NSRange  secondStartRange;
NSString *minuteString = @"";
if ( minuteRange.location != NSNotFound) 
{
    minuteString = [str substringWithRange: minuteRange];
    NSUInteger secondStartPt = NSMaxRange(minuteRange);
    secondStartRange = NSMakeRange(secondStartPt, str.length - secondStartPt);
}
else {
    secondStartRange = NSMakeRange(0, str.length);
}

NSRange secondRange = [str rangeOfString: secondPattern 
                                 options: NSRegularExpressionSearch
                                   range: secondStartRange];

NSString *secondString = @"";
if ( secondRange.location != NSNotFound) 
{
    secondString = [str substringWithRange: secondRange];
}

NSInteger minutes = [minuteString integerValue];
NSInteger seconds = [secondString integerValue];

NSLog(@"Minutes: %d, seconds: %d", minutes, seconds);

请注意，它会将5'21之类的字符串解析为5分21秒，不确定这是否是您想要的，但可以通过额外的测试来修复。

Answer 2

NSArray *data = @[@"3'15\"", @"3' 15\"", @"28\"", @"2'", @"50"];
NSString *pattern = @"(\\d++')|(\\d++(\"{0,1})$)";

NSRegularExpression *regExp = [NSRegularExpression regularExpressionWithPattern:pattern
                                                                        options:NSRegularExpressionCaseInsensitive
                                                                          error:nil];
for (NSString *string in data) {
    NSInteger mi = 0;
    NSInteger ss = 0;

    NSArray *match = [regExp matchesInString:string options:0 range:NSMakeRange(0,string.length)];
    for (NSTextCheckingResult *result in match) {

        NSString *value = [string substringWithRange:result.range];
        if ([value hasSuffix:@"'"]) {
            mi = [value integerValue];
        } else {
            ss = [value integerValue];
        }
    }
    NSLog(@"%@ - %d %d",string,mi,ss);
}

正则表达式提取分钟和秒

2 个答案: