我是NHibernate的新手,我正在尝试学习如何查询我的数据。
下面是配置xml。只显示配方。
我希望能够根据输入的关键字通过recipetitle查询食谱 以及来自ingredientname的成分。
所以你可以输入“面食酒”。
这是我尝试的但却给我一个错误。
hql = "from Recipe r " +
"left join r.Images " +
"inner join r.User " +
"inner join r.Ingredients i " +
"where i.IngredientName Like '%pasta%' OR i.IngredientName Like '%wine%' OR r.RecipeTitle Like '%pasta' OR r.RecipeTitle Like '%wine%'";
我也想加载收藏品。
我要正确查询吗? 我需要能够根据我的搜索条件构建查询字符串。 这在SQL中很容易形成。
马尔科姆
<class name="Recipe" table="Recipes" xmlns="urn:nhibernate-mapping-2.2">
<id name="RecipeID" type="Int32" column="RecipeID">
<generator class="identity" />
</id>
<property name="RecipeTitle" type="String">
<column name="RecipeTitle" />
</property>
<property name="Completed" type="Boolean">
<column name="Completed" />
</property>
<property name="ModifiedOn" type="DateTime">
<column name="ModifiedOn" />
</property>
<property name="Rating" type="Double">
<column name="Rating" />
</property>
<property name="PrepTime" type="Int32">
<column name="PrepTime" />
</property>
<property name="CookTime" type="Int32">
<column name="CookTime" />
</property>
<property name="Method" type="String">
<column name="Method" />
</property>
<bag name="Images" inverse="true" cascade="all">
<key column="RecipeID" />
<one-to-many class="OurRecipes.Domain.RecipeImage, OurRecipes.Domain, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null" />
</bag>
<many-to-one name="Category" column="CategoryID" />
<bag name="Comments" inverse="true" cascade="all">
<key column="RecipeID" />
<one-to-many class="OurRecipes.Domain.Comment, OurRecipes.Domain, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null" />
</bag>
<many-to-one name="User" column="EnteredByID" />
<bag name="Ingredients" inverse="true" cascade="all">
<key column="RecipeID" />
<one-to-many class="OurRecipes.Domain.Ingredient, OurRecipes.Domain, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null" />
</bag>
</class>
答案 0 :(得分:22)
要构建动态查询,我会使用条件API。这使得动态查询更加稳定,因为您不需要字符串操作来构建它。
ICriteria query = Session.CreateCriteria(typeof(Recipe), "r")
.CreateCriteria("Ingredients", "i", JoinType.InnerJoin)
.Add(
Expression.Disjunction() // OR
.Add(Expression.Like("i.IngredientName", "%pasta%"))
.Add(Expression.Like("i.IngredientName", "%wine%"))
.Add(Expression.Like("r.RecipeTitle", "%pasta%"))
.Add(Expression.Like("r.RecipeTitle", "%wine%")));
List<Recipe> result = query.List<Recipe>();
修改强>
对于急切加载,您可以设置获取模式:
ICriteria query = Session.CreateCriteria(typeof(Recipe), "r")
.SetFetchMode("Images", FetchMode.Join)
.SetFetchMode("Comments", FetchMode.Join)
.SetFetchMode("Ingredients", FetchMode.Join)
但我不会这样做因为你得到的结果乘以图像,评论和成分的数量。因此,如果您有4张图片,2条评论和12种成分,您可以获得96次食谱。您无法识别这一点,因为NHibernate会再次将事物放在一起,但它会在应用程序和数据库之间产生流量。所以最好让NHibernate用单独的查询加载它。
再一次编辑以显示动态查询合成。
// filter arguments, all are optional and should be omitted if null
List<string> keywords;
TimeSpan? minCookingTime;
TimeSpan? maxCookingTime;
int? minRating;
int? maxRating;
ICriteria query = Session.CreateCriteria(typeof(Recipe), "r");
if (keyword != null)
{
// optional join
query.CreateCriteria("Ingredients", "i", JoinType.InnerJoin);
// add keyword search on ingredientName and RecipeTitle
var disjunction = Expression.Disjunction();
foreach (string keyword in keywords)
{
string pattern = String.Format("%{0}%", keyword);
disjunction
.Add(Expression.Like("i.IngredientName", pattern))
.Add(Expression.Like("r.RecipeTitle", pattern));
}
query.Add(disjunction)
}
if (minCookingTime != null)
{
query.Add(Expression.Ge(r.CookingTime, minCookingTime.Value));
}
if (maxCookingTime != null)
{
query.Add(Expression.Le(r.CookingTime, maxCookingTime.Value));
}
if (minRating != null)
{
query.Add(Expression.Ge(r.Rating, minRating.Value));
}
if (maxRating != null)
{
query.Add(Expression.Le(r.Rating, maxRating.Value));
}
答案 1 :(得分:5)
Stefan和Sathish的例子都将%运算符连接到SQL中。这是不必要的,因为Restrictions.Like(nhib 2.0+)和Expression.Like(在v2.0之前)有3个参数版本和MatchMode。
Disjunction keywordsCriteria = Restrictions.Disjunction();
foreach (var keyword in keywords)
{
keywordsCriteria.Add(Restrictions.Like("i.IngredientName", keyword, MatchMode.Anywhere));
keywordsCriteria.Add(Restrictions.Like("r.RecipeTitle", keyword, MatchMode.Anywhere));
}
NHibernate Search也提供全文查询。有关详细信息,请参阅Ayende's example。
答案 2 :(得分:1)
以上是动态关键字的上述标准
string searchQuery = "wine pasta";
ICriteria query = Session.CreateCriteria(typeof(Recipe), "r")
.CreateCriteria("Ingredients", "i", JoinType.InnerJoin)
.SetFetchMode("Images", FetchMode.Join)
.SetFetchMode("Comments", FetchMode.Join)
.SetFetchMode("Ingredients", FetchMode.Join)
.SetResultTransformer(new DistinctRootEntityResultTransformer());
var keywords = searchQuery.Split(' ');
Disjunction keywordsCriteria = Restrictions.Disjunction();
foreach (var keyword in keywords)
{
keywordsCriteria.Add(Restrictions.Like("i.IngredientName", string.Format("%{0}%", keyword)));
keywordsCriteria.Add(Restrictions.Like("r.RecipeTitle", string.Format("%{0}%", keyword)));
}
query.Add(keywordsCriteria);
List<Recipe> result = query.List<Recipe>();