为什么不是我简单的Vector.cpp链接？ （从c ++开始）

Question

我直接从书中得到了.cpp和.h，似乎没有什么遗漏，但是我得到了这些链接错误....

#ifndef SIMPLEVECTOR_H
#define SIMPLEVECTOR_H
#include <iostream>
#include <new>          // needed for bad__alloc exception
#include <cstdlib>      // needed for the exit function
using namespace std;

template <class T>
class simplevector
{
private:
    T *aptr;
    int arraysize;
    void memerror(); // handles mem aloc errors
    void suberror(); // handles subscripts out of range
public:
    simplevector() // default constructor
    { aptr = 0; arraysize = 0; }
    simplevector(int); // constructor
    simplevector(const simplevector &); // coppy constructor
    ~simplevector();
    int size()
        { return arraysize; }
    T &operator[](const int &); // overloaded [] operator
};

template <class T>
simplevector<T>::simplevector(int s)
{
    arraysize = s;
    // allocate memory for the array
    try
    {
        aptr = new T [s];
    }
    catch (bad_alloc)
    {
        memerror();
    }

    // initialize the array.
    for (int count = 0; count < arraysize; count++)
        *(aptr + count) = 0;
}

template <class T>
simplevector<T>::simplevector(const simplevector &obj)
{
    arraysize = obj.arraysize;
    aptr = new T [arraysize];
    if (aptr == 0)
        memerror();
    for(int count = 0; count < arraysize; count++)
        *(aptr + count) = *(obj.aptr + count);
}

template <class T>
simplevector<T>::~simplevector()
{
    if (arraysize > 0)
        delete [] aptr;
}

template <class T>
void simplevector<T>::memerror()
{
    cout << "ERROR: Cannot allocate memory.\n";
    exit(0);
}

template <class T>
T &simplevector<T>::operator [](const int &sub)
{
    if (sub < 0 || sub >= arraysize)
        suberror();
    return aptr[sub];
}

#endif

此程序演示了simplevector模板：

#include <iostream>
#include "simplevector.h"
using namespace std;

int main()
{
    simplevector<int> inttable(10);
    simplevector<float> floattable(10);
    int x;

    //store values in the arrays.
    for (x = 0; x < 10; x++)
    {
        inttable[x] = (x * 2);
        floattable[x] = (x * 2.14);
    }

    //display the values in the arrays.
    cout << "these values are in inttable:\n";
    for (x = 0; x< 10; x++)
        cout << inttable[x] << " ";
    cout << endl;
    cout << "these values are in floattable:\n";
    for (x = 0; x< 10; x++)
        cout << floattable[x] << " ";
    cout << endl;

    //use the standard + operator on array elements.
    cout << "\nAdding 5 to each element of inttable"
        << " and floattable.\n";
    for (x = 0; x< 10; x++)
    {
        inttable[x] = inttable[x] + 5;
        floattable[x] = floattable[x] + 1.5;
    }

    //display the values in the array.
    cout << "These values are in inttable:\n";
    for (x = 0; x< 10; x++)
        cout << inttable[x] << " ";
    cout << endl;
    cout << "These values are in floattable:\n";
    for (x = 0; x< 10; x++)
        cout << floattable[x] << " ";
    cout << endl;
    // use the standard ++ operator on array elements.
    cout << "\nIncrementing each element of inttable and" 
        << " floattable.\n";
    for (x = 0; x< 10; x++)
    {
        inttable[x]++;
        floattable[x]++;
    }

    //display the values in the array.
    cout << "These values are in inttable:\n";
    for (x = 0; x< 10; x++)
        cout << inttable[x] << " ";
    cout << endl;
    cout << "These values are in floattable:\n";
    for (x = 0; x< 10; x++)
        cout << floattable[x] << " ";
    cout << endl;

    return 0;
}

Answer 1

您在OP评论中发布的错误就在那里 - 您在没有定义的情况下声明了simplevector::suberror。

Answer 2

suberror（）的胆量在哪里？我在类实现中没有看到。