Question

我搜索了很多但仍然无法正常工作，所有我的int和Strings等都不会改变他们的标签

我的解/序列化代码：

public void serialize()
{
   XmlSerializer xs = new XmlSerializer(typeof(Stundenplan));
   TextWriter writer = new StreamWriter(@"daten.xml");
   xs.Serialize(writer, this);
   writer.Close();
}  //seems to work since the xml file looks good

public void deserialization()
{
   XmlSerializer xs = new XmlSerializer(typeof(Stundenplan));
   TextReader reader = new StreamReader(@"daten.xml");
   Stundenplan stu;
   stu = (Stundenplan)xs.Deserialize(reader);
}  // don't see any change

以下是我参与序列化的类，没有所有的空白：

public class Stundenplan
{
    public Fach[] faecher = new Fach[100];
    public int fachnr = 0;

.......（很多空洞） }

public class Fach
{
    public String name;
    public bool[] stunden = new bool[8];
    public Hausaufgabe[] hausaufgaben = new Hausaufgabe[10000];
    public int hausaufgabennr = 0;
    public String lehrer;

....（也有几个空洞） }

public class Hausaufgabe
{
    public DateTime datum;
    public String beschreibung;
    public bool gemacht;

    public Hausaufgabe()
    {
    }
}

缺少什么/错误？

Answer 1

问题出在以下几行：

stu = (Stundenplan)xs.Deserialize(reader);

您要将值反序列化为另一个实例（stu而不是this），并在方法结束时将其丢弃。您应该像这样重写deserialization()方法：

public static Stundenplan deserialization()
{
    XmlSerializer xs = new XmlSerializer(typeof(Stundenplan));
    TextReader reader = new StreamReader(@"daten.xml");
    return (Stundenplan)xs.Deserialize(reader);
}

当然你也应该改变你的召唤方式：

Stundenplan sp = Stundenplan.deserialization();

而不是

Stundenplan sp = new Stundenplan();
sp.deserialization();

XmlSerializer不会显示对现有实例的更改

1 个答案: