Question

我有以下表格，带有“选择”标签：

  <form action="upload.php" enctype="multipart/form-data" method="post">
  <br>Filename:&nbsp;<input name="userfile" type="file">
  <p>Customer:&nbsp;      


  <select name="customer">

  <?php
include 'data.dat';
include 'error.inc';

// Connect to the database
if (!($connection = @ mysql_connect ($hostName,
                                    $username,
                                    $password)))

die ("Could not connect to database");

// Select the database
if (!mysql_select_db ($databaseName, $connection))
    showerror();

// Display all the available customers in order
$query = "SELECT customer FROM custlist order by id";

if (!($result = @ mysql_query ($query, $connection)))
    showerror();

$i = 0;

// Display each customer in a drop down menu. 
while ($row = @ mysql_fetch_array ($result))
{
    $i++;
    if ($i == 1)
        echo "<option value=" . $i . " selected>" . $row['customer'] . "\n";
    else
        echo "<option value=" . $i . ">" . $row['customer'] . "\n";
  //
}
  //


  ?>

  </select>
  <input type="submit" value="Upload file">
  </form>

由于数据库只有一行，只有一个客户，我希望消除组合框并自动选择唯一一个客户。我怎样才能做到这一点？我真的是一个新手，经过大量修改，我仍然没有找到解决方案。

感谢您的帮助。

垫

更新

感谢一些建议，我正在研究这个修改...仍然不起作用，但我认为是正确的方法，不是吗？

以下是代码：

  <select name="customer">

  <?php
include 'data.dat';
include 'error.inc';

// Connect to the database
if (!($connection = @ mysql_connect ($hostName,
                                    $username,
                                    $password)))

die ("Could not connect to database");

// Select the log database
if (!mysql_select_db ($databaseName, $connection))
    showerror();

// Display all the available customers in order
$query = "SELECT customer FROM curlist order by id";

  $result = mysql_query($query) or die(mysql_error());


  $row = mysql_fetch_array($result) or die(mysql_error());
  echo  $row['customer'];


  ?>

  </select>

Answer 1

根据建议，我将其作为答案发布：

$count = mysql_num_rows($result);

if($count == 1) {
    $row = mysql_fetch_assoc($result);
    echo '<input type="text" value="' . htmlentities($row['customer']) . '" readonly />';
    echo '<input type="hidden" name="customer" value="..." />';
} else {
    echo '<select name="customer">';
    while($row = mysql_fetch_assoc($result)) {
        echo '<option value="...">' . htmlentities($row['customer']) . '</option>';
    }
    echo '</select>';
}

值中的...理想情况下是表格中的某种主键。

Answer 2

在调用mysql_query之后，您应该调用mysql_num_rows()来查找从SELECT语句返回的行数，如果为1，则继续而不显示select。

Answer 3

您无法消除硬编码到HTML结构中的组合框。

使用以下内容将此HTML合并到您的代码中：

// Get number of rows returned by query
$count = mysql_num_rows($result);

// Start iteration counter
$i = 1; # start at one to marry up with $count

// Iterate through array of mySQL rows
while ($row = mysql_fetch_array($query, MYSQL_ASSOC)) {

    if ($count == 1) {  # Evals true if 1 customer is returned
        $html = "<input type=\"textbox\" value=\"". $row['customer'] . "\" />";

    // If multiple customers are returned, 
    // but it's the first iteration through the loop. Create Select box.
    } elseif ($i == 1 && $count != 1) { 

        $html .= "<select name=\"customer\">\n";
        $html .= "<option value=\"" . $row['id'] . "\">" . $row['customer'] . "</option>\n";

    // If this is the last row, close the select box.
    } elseif ($i == $count) {
        // 
        $html .= "<option value=\"" . $row['id'] . "\">" . $row['customer'] . "</option>\n";
        $html .= "</select>\n";

    // If none of the above, create new option
    } else {
        $html .= "<option value=\"" . $row['id'] . "\">" . $row['customer'] . "</option>\n";
    }

    $i++;
}

echo $html;

编辑：从下面的评论中，将<option>值属性更改为客户行ID。

如何从表单中删除组合框

3 个答案: