我已经四处寻找,似乎无法得到正确的答案。我想替换给定HTML字符串中的所有链接,如下所示:
... <a href="link.php">Description Here</a> ...
to:
Description Here: link.php
这样非HTML电子邮件客户端就可以看到该链接,并且能够将它们复制并粘贴到浏览器中。
答案 0 :(得分:1)
你可以这样做:
$text = '<a href="link.php">Description Here</a>';
$replaced = preg_replace('/<a [^>]*href="(.*)"[^>]*>(.*)<\/a>/', '$2: $1', $text);
答案 1 :(得分:1)
PCRE救你:
$text = '<a href="link.php">Description Here</a>';
echo preg_replace("/\<a.*href=\"(.*)\".*\>(.*)\<\/a\>/Usi",'$2: $1',$text);
答案 2 :(得分:1)
echo preg_replace("/<a.*?href=\"(.*?)\".*?>(.*?)<\/a>/i", "$2: $1", $html);
答案 3 :(得分:1)
在来自通用html文件的纯PHP中,您可以:
<?php
//an example html string
$dataStr = '<ul id="sub-menu">
<li class="parent item10"><a href="link1.php">Arts</a>
<ul>
<li class="item29">
<a href="link2.php">Arts Show</a></li>
<li class="item29">
<a href="link3.php">Another Arts Show</a></li>
</ul>
</li>
<li class="parent item15"><a href="link6.php">News</a>
<ul>
<li class="item18">
<a href="link7.php">News Show</a></li>
</ul>
</li>
</ul>';
$startIndex = strpos($dataStr, "<a", 0);
$endIndex = strpos($dataStr, "</a", $startIndex);
while (1==1){
if($startIndex == false || $endIndex == false){
break;
}
$currentLine = substr($dataStr,$startIndex,($endIndex-$startIndex)+4);
$linkStartIndex = strpos($currentLine, "href=", 0)+6;
$linkEndIndex = strpos($currentLine, '"', $linkStartIndex);
$currentLink = substr($currentLine,$linkStartIndex,$linkEndIndex-$linkStartIndex);
$descriptionStartIndex = strpos($currentLine, ">", $linkEndIndex)+1;
$descriptionEndIndex = strpos($currentLine, "<", $descriptionStartIndex);
$currentDescription = substr($currentLine,$descriptionStartIndex,$descriptionEndIndex-$descriptionStartIndex);
echo ($currentDescription.": ".$currentLink."\n");
$startIndex = strpos($dataStr, "<a", $endIndex+5);
$endIndex = strpos($dataStr, "</a", $startIndex);
}
?>