野牛:冲突:1班/减少错误

时间:2011-12-03 16:40:05

标签: parsing compiler-construction bison yacc

我正在尝试用野牛构建一个解析器,并将我的所有错误缩小到一个难度。

以下是bison的调试输出,其中包含错误所在的状态:

state 120

   12 statement_list: statement_list . SEMICOLON statement
   24 if_statement: IF conditional THEN statement_lists ELSE statement_list .

    SEMICOLON  shift, and go to state 50

    SEMICOLON  [reduce using rule 24 (if_statement)]
    $default   reduce using rule 24 (if_statement)

以下是parser.y source

中的翻译规则
%%

program              : ID COLON block ENDP ID POINT
                     ;
block                : CODE statement_list
                     | DECLARATIONS declaration_block CODE statement_list
                     ;
declaration_block    : id_list OF TYPE type SEMICOLON
                     | declaration_block id_list OF TYPE type SEMICOLON
                     ;
id_list              : ID
                     | ID COMMA id_list
                     ;
type                 : CHARACTER
                     | INTEGER
                     | REAL
                     ;
statement_list       : statement
                     | statement_list SEMICOLON statement
                     ;
statement_lists      : statement
                     | statement_list SEMICOLON statement
                     ;
statement            : assignment_statement
                     | if_statement
                     | do_statement
                     | while_statement
                     | for_statement
                     | write_statement
                     | read_statement
                     ;
assignment_statement : expression OUTPUTTO ID
                     ;
if_statement         : IF conditional THEN statement_lists ENDIF
                     | IF conditional THEN statement_lists ELSE statement_list
                     ;
do_statement         : DO statement_list WHILE conditional ENDDO
                     ;
while_statement      : WHILE conditional DO statement_list ENDWHILE
                     ;
for_statement        : FOR ID IS expression BY expressions TO expression DO statement_list ENDFOR
                     ;
write_statement      : WRITE BRA output_list KET
                     | NEWLINE
                     ;
read_statement       : READ BRA ID KET
                     ;
output_list          : value
                     | value COMMA output_list
                     ;
condition            : expression comparator expression
                     ;
conditional          : condition
                     | NOT conditional
                     | condition AND conditional
                     | condition OR conditional
                     ;
comparator           : ASSIGNMENT
                     | BETWEEN
                     | LT
                     | GT
                     | LESSEQUAL
                     | GREATEREQUAL
                     ;
expression           : term
                     | term PLUS expression
                     | term MINUS expression
                     ;
expressions          : term
                     | term PLUS expressions
                     | term MINUS expressions
                     ;
term                 : value
                     | value MULTIPLY term
                     | value DIVIDE term
                     ;
value                : ID
                     | constant
                     | BRA expression KET
                     ;
constant             : number_constant
                     | CHARCONST
                     ;
number_constant      : NUMBER
                     | MINUS NUMBER
                     | NUMBER POINT NUMBER
                     | MINUS NUMBER POINT NUMBER
                     ;              
%%

当我删除if_statement规则时没有错误,所以我大大缩小了它,但仍然无法解决错误。

感谢您的帮助。

2 个答案:

答案 0 :(得分:3)

考虑这个陈述:如果条件则s2否则s3; S4

有两种解释:

if condition then
   s1;
else 
   s2;
s3;

另一个是:

if condition then
   s1;
else
   s2;
   s3;

在第一个中,法规列表由if语句和s3组成。而另一个语句只由一个if语句组成。这就是歧义的来源。当存在shift-reduce冲突时,Bison会选择shift to reduce,因此在上述情况下,解析器将选择转换s3

由于ENDIF语句中有if-then,请考虑在ENDIF语句中引入if-then-else,然后问题就解决了。

答案 1 :(得分:2)

我认为您在ENDIF规则中缺少IF-THEN-ELSE-ENDIF