Question

当我按下屏幕上的图像时，它调用powerButton.OnClickListener（）就像它应该的那样，并且在几秒钟的缓冲之后，流播放得很好。然而，人们希望显示一个简短的吐司弹出窗口以通知用户“无线电流连接，请等待......”

这就是问题所在，无论我尝试过什么，我在哪里设置了创建Toast弹出窗口的行，它在进入缓冲之前根本不会显示。

我们将非常感谢任何帮助，并且我已添加了大部分代码，并在必要时提供更多代码。

        // run on powerButton click
    powerButton.setOnClickListener(new OnClickListener()
        {
        public void onClick(View view)
        {
            // check if the player is started or stopped
            if (isPlaying) // player is streaming
            {
                // stop the stream and set isPlaying to false
                mediaPlayer.stop();

                // release the media player
                releaseMediaPlayer();

                // update notification
                mNotificationManager.cancel(SIMPLE_NOTFICATION_ID);

                // set power button to "powered off" image
                powerButton.setImageResource(R.drawable.power_off);
            }
            else // player not streaming
            {
                // notify the user that the stream is loading
                final Toast streamLoading = toast.makeText(getBaseContext(), "Radio Stream Connecting, Please Wait...", Toast.LENGTH_SHORT);
                streamLoading.show();

                // try catch block to attempt connecting to radioUrl
                try
                {                       
                    // create new instance of media player
                    mediaPlayer = new MediaPlayer();

                    // set media player to handle audio streams                    
                    mediaPlayer.setAudioStreamType(AudioManager.STREAM_MUSIC);

                    // connect to radio stream and fill buffer
                    mediaPlayer.setDataSource(radioUrl);
                    mediaPlayer.prepare(); // might take long depending on buffering speed

                    // start the media player and set isPlaying to true
                    mediaPlayer.start();
                    isPlaying = true;

                    // update notification, clear stream message
                    createNotification();

                    // set power button to "powered on" image
                    powerButton.setImageResource(R.drawable.power_on);
                }
                catch (IllegalArgumentException e) // cannot connect to stream
                {
                    // clear streaming text and notify user of failure
                    final Toast streamError1 = Toast.makeText(MainMenu.this, "Failed to load: Unable to connect to stream!", Toast.LENGTH_SHORT);
                    streamError1.show();

                    // release the media player and display error
                    releaseMediaPlayer();
                    mNotificationManager.cancel(SIMPLE_NOTFICATION_ID);
                    e.printStackTrace();
                }
                catch (IllegalStateException e) // stream cannot play audio
                {
                    // clear streaming text and notify user of failure
                    final Toast streamError2 = Toast.makeText(getBaseContext(), "Failed to load: cannot play stream!", Toast.LENGTH_SHORT);
                    streamError2.show();

                    // release the media player and display error
                    releaseMediaPlayer();
                    mNotificationManager.cancel(SIMPLE_NOTFICATION_ID);
                    e.printStackTrace();
                }
                catch (IOException e) // general connection issue
                {
                    // clear streaming text and notify user of failure
                    final Toast streamError3 = Toast.makeText(getBaseContext(), "Failed to Load: Connection issue!", Toast.LENGTH_SHORT);
                    streamError3.show();

                    // release the media player and display error
                    releaseMediaPlayer();
                    mNotificationManager.cancel(SIMPLE_NOTFICATION_ID);
                    e.printStackTrace();
                }
            }

        }
    });

Answer 1

那是因为在你从onClick返回之前，toast不会显示，因为那是UI线程。我在缓冲开始之后才会这样做。我想要获得你想要的效果，你检查AsynchTask在后台线程中进行缓冲并立即返回onClick。

事实上你正在这样做的方式，如果缓冲时间过长你的应用程序将被标记为没有响应的android。

Answer 2

尝试使用AsyncTask，其中AsyncTask做的第一件事就是在进入缓冲过程之前显示吐司。

从来没有叫过吐司线

2 个答案: