Node.js - 需要空路径

时间:2011-12-02 16:40:22

标签: javascript node.js

我在github上遇到this file,这样做:

var migrate = require('../')

这是什么意思?当我尝试相同的时候,我得到:Error: Cannot find module '../'

2 个答案:

答案 0 :(得分:13)

它需要父文件夹的文件index.js,即此文件:https://github.com/visionmedia/node-migrate/blob/master/index.js

答案 1 :(得分:2)

以下是官方节点js网站上的文档。我只是在这里完成了所有步骤,但就你的问题而言,找到----这就是你想知道的东西----

require(X) from module at path Y
1. If X is a core module,
   a. return the core module
   b. STOP
2. If X begins with './' or '/' or '../'
   a. LOAD_AS_FILE(Y + X)
   b. LOAD_AS_DIRECTORY(Y + X)
3. LOAD_NODE_MODULES(X, dirname(Y))
4. THROW "not found"

LOAD_AS_FILE(X)
1. If X is a file, load X as JavaScript text.  STOP
2. If X.js is a file, load X.js as JavaScript text.  STOP
3. If X.json is a file, parse X.json to a JavaScript Object.  STOP
4. If X.node is a file, load X.node as binary addon.  STOP

LOAD_AS_DIRECTORY(X) ---- here is what you wanted to know ----
1. If X/package.json is a file,
   a. Parse X/package.json, and look for "main" field.
   b. let M = X + (json main field)
   c. LOAD_AS_FILE(M)
2. If X/index.js is a file, load X/index.js as JavaScript text.  STOP
3. If X/index.json is a file, parse X/index.json to a JavaScript object. STOP
4. If X/index.node is a file, load X/index.node as binary addon.  STOP

更多信息,请查看https://nodejs.org/api/modules.html#modules_all_together