Question

$array = array("2011-September_38","2011-June_4","2010-November_9","2011-November_29","2010-December_19");

我想按如下方式对这个数组字符串进行排序，它应该先对年份进行排序，然后对它进行排序，

渴望输出

Array ( [0] => 2010-Marh_19 
        [1] => 2010-November_9 
        [2] => 2011-June_4 
        [3] => 2011-September_38
        [4] => 2011-November_29 )

我尝试了一些东西，任何人都可以将我的功能绑定到年份http://codepad.org/skEiUkTC

Answer 1

试试这段代码：

<?php
$array = array("2011-September_38","2011-June_4","2010-November_9","2011-November_29","2010-December_19");
function monthCompare($a, $b) {
   $da = strtotime(strstr($a, '_', true));
   $db = strtotime(strstr($b, '_', true));
   return $da > $db;
}
usort($array, "monthCompare");
print_r($array);
?>

<强>输出

Array
(
    [0] => 2010-November_9
    [1] => 2010-December_19
    [2] => 2011-June_4
    [3] => 2011-September_38
    [4] => 2011-November_29
)

Answer 2

对此的一个简单解决方案是将每个值转换为具有DateTime::createFromFormat的对象，对它们进行排序，然后再次输出值。

在我看到这个问题之前，我从来没有玩过DateTime对象，但它们很棒且易于使用，createFromFormat非常有意义。

$array = array("2011-September_30","2011-June_4","2010-November_9","2011-November_29","2010-December_19");

foreach($array as $item)
{
    $timestamps[] = DateTime::createFromFormat('Y-F_d',$item);
}

sort($timestamps);

foreach($timestamps as $timestamp)
{
    $newarray[] = $timestamp->format('Y-F_d');
}

会给你

Array
(
    [0] => 2010-November_09
    [1] => 2010-December_19
    [2] => 2011-June_04
    [3] => 2011-September_30
    [4] => 2011-November_29
)

如何从PHP中的值数组中排序特定的字符串？

2 个答案: