我收到以下错误:
<my correct path>/applicationContext_AuthService.xml]: Invocation of init method failed; nested exception is org.hibernate.InvalidMappingException: Unable to read XML
然后进一步向下揭示了原因:
Caused by: org.xml.sax.SAXParseException: The content of element type "hibernate-mapping" must match "(meta*,identifier-generator*,typedef*,filter-def*,import*,(class|subclass|joined-subclass|union-subclass)*,resultset*,(query|sql-query)*,filter-def*,fetch-profile*,database-object*)".
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:195)
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.error(ErrorHandlerWrapper.java:131)
异常是引用文件applicationContext_AuthService.xml。在那里,我有以下映射:
<bean id="UserAPPSessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="UserAPP" />
</property>
<property name="mappingResources">
<list>
<!-- value>hib/userapp/ActionImpl.hbm.xml</value -->
<value>hib/userapp/ActivityCode.hbm.xml</value>
<value>hib/userapp/Authorization.hbm.xml</value>
<value>hib/userapp/Contacts.hbm.xml</value>
<value>hib/userapp/CorrectionRequests.hbm.xml</value>
<!-- value>hib/userapp/CSRHistory.hbm.xml</value -->
<value>hib/userapp/Csrusers.hbm.xml</value>
<value>hib/userapp/Customer.hbm.xml</value>
<value>hib/userapp/CustomerTypeImpl.hbm.xml</value>
<value>hib/userapp/DocumentAssociationCrosswalk.hbm.xml</value>
<value>hib/userapp/DocumentImpl.hbm.xml</value>
<value>hib/userapp/KeyDB.hbm.xml</value>
<value>hib/userapp/KeyDBFirst.hbm.xml</value>
<value>hib/userapp/NotesImpl.hbm.xml</value>
<value>hib/userapp/Product.hbm.xml</value>
<value>hib/userapp/RatesImpl.hbm.xml</value>
<value>hib/userapp/ReminderImpl.hbm.xml</value>
<value>hib/userapp/YearImpl.hbm.xml</value>
</list>
</property>
第二个是hib / userapp / Authorization.hbm.xml。这是该文件:
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated Aug 17, 2011 3:35:48 PM by Hibernate Tools 3.4.0.CR1 -->
<hibernate-mapping>
<class name="com.eagle.customer.impl.AuthorizationImpl" table="CustomerAuthorization"
schema="dbo" catalog="UserAPP">
<cache usage="read-write" />
<id name="custId" type="string">
<column name="CustID" length="10" />
<generator class="assigned" />
</id>
<property name="password" type="string">
<column name="Password" length="15" />
</property>
<property name="custType" type="string">
<column name="CustType" length="10" />
</property>
<property name="authLevel" type="string">
<column name="AuthLevel" length="2" />
</property>
<property name="custStatus" type="string">
<column name="CustStatus" length="10" />
</property>
<property name="vincaptureHbm" type="string">
<column name="VINCapture" length="1" />
</property>
<property name="mileageReportHbm" type="string">
<column name="MileageReport" length="1" />
</property>
</class>
我认为这是抱怨的。根据XMLSpy,它是有效的xml。
有人对我做错了什么有任何想法吗?
提前致谢,
安德鲁
答案 0 :(得分:1)
你错过了最后一行,除非这是一个复制粘贴错误:
</hibernate-mapping>
你能确认这是这个档案吗?尝试将其评论出来,看看错误是否消失(或者给出了不同的错误)。