Question

免责声明：我是Web开发的新手

到目前为止：我一直在将MySQL数据库表中的主键数据传递到生成日历时显示在日历类库列表项的id =“”字段中，而且我也一直在传递另一个与列表项的相应主键的行相关联的值。

场景：我需要将主键的相同行中的另一个值传递到列表项的class =“”，然后我就碰壁了。我可能需要在我的模态中创建一个新函数，或者在生成所述日历的控制器中执行某些操作，或者我可能完全忽略了一些非常简单的操作。无论如何，我可以使用一些非常赞赏的帮助。非常感谢你！

P.S。如果您需要更多信息来帮助我，请告诉我。再次感谢！你太棒了！

型号：

class Events_model extends crud_model {

    public function __construct()
    {
        parent::__construct();

        $this->pk = 'id';
        $this->table_name = 'events';
    }

    public function get_events_for_calendar($user_id, $year = FALSE, $month = FALSE)
    {

        if ( ! $year )
        {
            $year = date("Y");
        }

        if ( ! $month )
        {
            $month = date("m");
        }

        $this->db->where("user_id", $user_id);
        $events = parent::get_all();

        $cal_events = array();

        foreach ($events as $e)
        {
            if ( date("Y", $e->date) == $year && date("m", $e->date) == $month)
            {       
                $day = intval( date("d", $e->date));

                //Swap out to change between displaying type or title of events listed -lrussell810

                //$cal_events[$day][$e->id] = $e->type;
                $cal_events[$day][$e->id] = $e->title;
            }
        }
        return $cal_events;
    }

控制器：

$this->load->library('calendar', $config);

        $title['title'] = 'Planner';

        $data = $this->events->get_events_for_calendar($this->end_user->id, $this->uri->segment(4), $this->uri->segment(5));

        $calendar['calendar'] = $this->calendar->generate($this->uri->segment(4), $this->uri->segment(5), $data);

        $this->load->view('public/head_view', $title);
        $this->load->view('user/header_view');
        $this->load->view('user/planner_view', $calendar);
        $this->load->view('user/footer_view');

日历库：

// If more than one event on the same day
                      if (is_array($data[$day]))
                      {
                        $several_events = '';
                        foreach ($data[$day] as $key => $value)
                        {
                          $several_events .= '<li class="" id="'.$key.'">'.$value.'</li>';
                        }
                        $out .= str_replace('{day}', $day, str_replace('{content}', $several_events, $temp));
                      }

其他日历资料库信息：

// --------------------------------------------------------------------

    /**
     * Initialize the user preferences
     *
     * Accepts an associative array as input, containing display preferences
     *
     * @access  public
     * @param   array   config preferences
     * @return  void
     */
    function initialize($config = array())
    {
        foreach ($config as $key => $val)
        {
            if (isset($this->$key))
            {
                $this->$key = $val;
            }
        }
    }

Answer 1

如果我理解正确，当你的视频以html形式输出时，你想要为你的事件添加“更多”，所以你要添加引用pk作为ID（因此我在上面的评论）。

您可以为每个事件创建一个关联数组，如下所示：

    $cal_events = array();

    foreach ($events as $e)
    {
        if ( date("Y", $e->date) == $year && date("m", $e->date) == $month)
        {       
            $day = intval( date("d", $e->date));

            //just made up examples below
            $cal_events[$day][$e->id]['class'] = $e->class;
            $cal_events[$day][$e->id]['type'] = $e->type;
            $cal_events[$day][$e->id]['id'] = $e->title; 
        }
    }
    return $cal_events;

稍后您将在日历库中引用该数组，如下所示：

// If more than one event on the same day
if (is_array($data[$day])){
    $several_events = '';
    foreach ($data[$day] as $key => $value)
    {
        $several_events .= '<li class="'.$value['class'].'" id="'.$value['id'].'">'.$value['type'].'</li>';
    }
    $out .= str_replace('{day}', $day, str_replace('{content}', $several_events, $temp));
}

希望这就是你要找的东西。

将数据从数据库传递到CodeIgniter日历库

1 个答案: