Question

我正在研究基于ARM的微控制器lpc2468。我无法配置控制器的UART1。以前我使用UART0用于相同的目的，但由于硬件的一些变化，我现在必须使用UART1。

我想将GPRS模块（SIMCOM 300）连接到微控制器的UART1。到目前为止，这是我的代码：

void init_serial_gprs (void){
    PINSEL7  |= 0x0000000F;
    U1LCR  = 0x00000080;
    U1DLL  = 0x00000041;
    U1DLM  =   0x00000000;
    U1LCR  = 0x03;
    VICVectAddr7 = (unsigned)serial1_isr;
    VICIntEnable = 1 << 7;
    SBUF= U1RBR;
    U1IER = 3;
}

void serial1_isr(void) __irq {
    volatile char dummy;
    volatile UWORD32 IIR1;

    /*------------------------------------------------
     Repeat while there is at least one interrupt source.
     ------------------------------------------------*/
    while (((IIR1 = U1IIR) & 0x01) == 0)
    {
        switch (IIR1 & 0x0E)
        {
            case 0x06: /* Receive Line Status */
                dummy = U1LSR;  /* Just clear the interrupt source */
                break;

            case 0x04: /* Receive Data Available */
            case 0x0C: /* Character Time-Out */
                SBUF= U1RBR;
                if(genflag.fl_m_psw || new_st == 0 ||new_st == 0x1f){
                    if(genflag.gprs_con)  receive_data();
                    else
                        receive_data_gprs();
                }
                break;

            case 0x02: /* THRE Interrupt */
                if(genflag.gprs_con) transfer_data();
                else transfer_data_gprs();
                dummy   = U1LSR;
                break;

            default:
                break;
        }
    }
    VICVectAddr = 0; /* Acknowledge Interrupt */
}

Answer 1

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在lpc 2468中配置UART1

1 个答案: