我有两张桌子。
users:
uid | city | username | flag |
10 | New York | john | 1 |
14 | Tokyo | kawasaki | 1 |
15 | Tokyo | coder | 1 |
groupmember:
id | uid | groupid |
1 | 10 | 16 |
2 | 14 | 16 |
3 | 15 | 21 |
两个表中的'uid'
都相同。
我想选择所有位于城市“tokyo”的用户,他们也是groupid“16”的组。
所以查询resutl应该是(在这种情况下)
14 | Tokyo | kawasaki | 1 |
答案 0 :(得分:3)
SELECT u.uid, u.city, u.username, u.flag
FROM users u
JOIN groupmember g ON u.uid = g.uid
WHERE u.city = 'Tokyo'
AND g.groupid = 16;
答案 1 :(得分:2)
select u.* from users u join groupmember gm on u.uid = gm.uid
where u.city='Tokyo' and gm.groupid=16
答案 2 :(得分:0)
SELECT u.uid, u.city, u.username, u.flag
FROM users u, groupmember g
WHERE u.uid = g.uid
AND u.city = 'Tokyo'
AND g.groupid = 16;
答案 3 :(得分:0)
SELECT * FROM
users INNER JOIN groupmember
ON users.uid = groupmember.uid
AND groupmember.groupid = 16
AND users.city = 'Tokyo'