EmbeddedId，sequence和ConstraintViolationException

Question

我有实体，有@EmbeddedId。在id类中有几个字段，其中一个是具有生成类型序列的Long id。当我尝试插入此实体的实例时，问题出现，而没有在embeeded id（应该从序列中插入）中设置id。

org.hibernate.exception.ConstraintViolationException: Could not execute JDBC batch update

当此embeddedId中的id设置为任何值时，insert为successl。

我该怎么做才能让它发挥作用？

编辑：代码

@Entity
@Table(name = "TestIds")
public class TestIds implements Serializable {

    @EmbeddedId
    private TestId testId;

    public TestIds(TestId testId) {
        this.setTestId(testId);
    }

    public TestId getTestId() {
    return testId;
    }

    public void setTestId(TestId testId) {
    this.testId = testId;
    }   
}

@Embeddable
public class TestId implements Serializable {

    private static final long serialVersionUID = 1L;
    @GeneratedValue(strategy=GenerationType.AUTO, generator="my_entity_seq_gen")
    @SequenceGenerator(name="my_entity_seq_gen", sequenceName="MY_ENTITY_SEQ")
    @Column(name = "column_name")
    private Long id;

    public TestId() {

    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }
}

我正在执行

TestIds a = new TestIds(new TestId());
Session session = sessionFactory.getCurrentSession();

session.save(a);
session.flush();

org.hibernate.exception.ConstraintViolationException: Could not execute JDBC batch update

Caused by: 
java.sql.BatchUpdateException: Batch entry 0 insert into TestIds (column_name) values (NULL) was aborted

Answer 1

似乎无法在@EmbeddedId

中使用@GeneratedValue

Answer 2

你应该将注释@GeneratedValue添加到id中，并采取你选择的行为。

例如为@Id

的错误编辑

@GeneratedValue(strategy=GenerationType.AUTO, generator="my_entity_seq_gen")
@SequenceGenerator(name="my_entity_seq_gen", sequenceName="MY_ENTITY_SEQ")
@Column(name = "column_name")
private Long id;