Question

如果我有2个时间变量：

    a = 00:00:12 and b = 00:00:05

如何将它们组合在一起制作：

    c = 00:00:17 ?

然后我需要将它们分成平均值，但我坚持添加部分。

我以这种格式从数据库中获取数据，当我尝试一个简单的时候：

    c=a+b;

我得到：

如何对时间变量实现简单的数学运算？

Answer 1

$date['first'] = DateTime::createFromFormat('H:i:s', "00:00:12");
$date['second'] = DateTime::createFromFormat('H:i:s', "00:00:05");

$interval = new DateInterval('PT'. $date['second']->format('s') .'S');

$date['first']->add($interval);

echo $date['first']->format('s'); // echoes 17

Answer 2

只需对所有操作使用mktime，然后在输出日期时将其转换回可读格式（使用date）：

$a = mktime(0, 0, 12);
$b = mktime(0, 0, 5);

echo date('G:i:s', $a + $b);
echo date('G:i:s', ($a + $b) / 2);

Answer 3

在MySQL中你可以这样做 -

SET @a = '00:00:12';
SET @b = '00:00:05';

SET @a_sec = TIME_TO_SEC(@a);
SET @b_sec = TIME_TO_SEC(@b);

SET @c_sec = @a_sec + @b_sec;

SELECT SEC_TO_TIME(@c_sec);
+---------------------+
| SEC_TO_TIME(@c_sec) |
+---------------------+
| 00:00:17            |
+---------------------+

Answer 4

或者你只是直接前进; - ）

<?php
$a = "00:00:12";
$b = "00:00:05";

function addTime($timeA, $timeB) {
    $timeAcomponents = explode(":", $timeA);
    $timeBcomponents = explode(":", $timeB);

    $timeAinSeconds = $timeAcomponents[0]*60*60 + $timeAcomponents[1]*60 + $timeAcomponents[2];
    $timeBinSeconds = $timeBcomponents[0]*60*60 + $timeBcomponents[1]*60 + $timeBcomponents[2];

    $timeABinSeconds = $timeAinSeconds + $timeBinSeconds;

    $timeABsec = $timeABinSeconds % 60;
    $timeABmin = (($timeABinSeconds - $timeABsec) / 60) % 60;
    $timeABh = ($timeABinSeconds - $timeABsec - $timeABmin*60) / 60 / 60;

    return str_pad((int) $timeABh,2,"0",STR_PAD_LEFT).":"
          .str_pad((int) $timeABmin,2,"0",STR_PAD_LEFT).":"
          .str_pad((int) $timeABsec,2,"0",STR_PAD_LEFT);
}

echo "Adding time variables:\n";
echo "$a + $b = ".addTime($a, $b);
?>

关于时间变量的数学运算

4 个答案: