Question

我有图表系列：

Series[] tempSeries = new Series[sensorNum];    // Series to hold current/past temperature data for plotting, for each sensor

我向他们添加新点：

tempSeries[i].Points.AddXY(current_time, temp_F[i]);        // Add new temperature data to series

现在我想将系列转换为字符串以通过套接字发送。

问题是如何从系列中获得Y值？

我试过了：

private string sendAll() {
        string myMsg = "";
        double[,] lastTemp = new double[4, 1200];
        double[,] lastWind = new double[4, 1200];
        for (int i = 0; i < 4; i++) {
            for (int j = 0; j < 1200; j++){
                try
                {
                    lastTemp[i, j] = tempSeries[i].Points[j].YValues[0];
                    myMsg += lastTemp[i, j] + " ";
                }
                catch (Exception ex) {
                    lastTemp[i, j] = 0;
                    myMsg += 0 + " ";
                }
            }
        }
        myMsg += "; ";

        for (int i = 0; i < 4; i++)
        {
            for (int j = 0; j < 1200; j++)
            {
                try
                {
                    lastWind[i, j] = windSeries[i].Points[j].YValues[0];
                    myMsg += lastWind[i, j] + " ";
                }
                catch (Exception ex)
                {
                    lastWind[i, j] = 0;
                    myMsg += 0 + " ";
                }
            }
        }
        MessageBox.Show(myMsg);

        return myMsg;
    }

但我的节目很冷......

Answer 1

也许这不是你的代码唯一的问题，但你永远不应该在循环中使用字符串连接（myMsg += 0 + " "; ...）因为字符串是不可变的。请改用StringBuilder课程。像这样：

    StringBuilder sb = new StringBuilder(); 
    for (int i = 0; i < 10000; i++)
    {
        sb.Append("x");
    } 
    string x = sb.ToString();

以下是有关字符串不可变的原因及其后果的详细信息： http://en.morzel.net/post/2010/01/26/Why-strings-are-immutable-and-what-are-implications-of-it.aspx

从c＃图表系列中获取y值？

1 个答案: