Question

我的数据库中有一个通知表，其中包含以下属性：timestamp:datetime和read:boolean。我想要的是查询和订购我的通知;首先，如果他们被阅读，然后他们已经获得时间戳，然后将通知量限制为10。

我试过的查询看起来像这样：

@user.notifications.order_by([[:read,:desc],[:timestamp,:desc]]).limit(10)

这只会给我一个错误，我将其缩小到证明布尔字段是罪魁祸首。

是否存在按真/假值排序的方法，还是应该使用某种自定义字段序列化将True和False转换为1和0？

Answer 1

你指定的内容适用于Mongoid 2.4.10，mongo 1.3，rails 3.2.3。希望以下内容有助于解决您的问题。

class User
  include Mongoid::Document

  field :name, type: String
  has_many :notifications
end

class Notification
  include Mongoid::Document

  field :read, type: Boolean
  field :timestamp, type: DateTime
  belongs_to :user
end

测试/单元/ notification_test.rb

require 'test_helper'

class NotificationTest < ActiveSupport::TestCase
  def setup
    User.delete_all
    Notification.delete_all
  end

  test "order_by boolean" do
    @user = User.create(name: 'Gary')
    [
      [true, 1.day.ago], [false, 2.days.ago], [false, 3.days.ago], [true, 5.days.ago], [false, 8.days.ago], [true, 11.days.ago],
      [false, 4.days.ago], [true, 6.days.ago], [true, 7.days.ago], [false, 9.days.ago], [false, 10.days.ago]
    ].each do |read, timestamp|
      @user.notifications << Notification.create(read: read, timestamp: timestamp)
    end
    assert_equal(1, User.count)
    assert_equal(11, Notification.count)
    result = @user.notifications.order_by([[:read,:desc],[:timestamp,:desc]]).limit(10).to_a
    assert_equal(10, result.size)
    result.each do |r|
      p [r.read, r.timestamp]
    end
  end
end

测试输出

Run options: --name=test_order_by_boolean

# Running tests:

[true, Mon, 28 May 2012 12:33:49 -0400]
[true, Thu, 24 May 2012 12:33:49 -0400]
[true, Wed, 23 May 2012 12:33:49 -0400]
[true, Tue, 22 May 2012 12:33:49 -0400]
[true, Fri, 18 May 2012 12:33:49 -0400]
[false, Sun, 27 May 2012 12:33:49 -0400]
[false, Sat, 26 May 2012 12:33:49 -0400]
[false, Fri, 25 May 2012 12:33:49 -0400]
[false, Mon, 21 May 2012 12:33:49 -0400]
[false, Sun, 20 May 2012 12:33:49 -0400]
.

Finished tests in 0.023062s, 43.3614 tests/s, 130.0841 assertions/s.

1 tests, 3 assertions, 0 failures, 0 errors, 0 skips

Mongoid order_by boolean

1 个答案: