我在ASP.NET项目中使用LINQ to SQL。在插入表时,我需要将值转换为特定的表对象,我需要插入。
为此我在该表中创建了一个带有参数的新构造函数,以便我可以将我的值赋给该表对象,分配功能正在工作但插入(obj.TS_Questions.InsertOnSubmit(mytableobject);
时)我得到null异常。
我的代码::
default constructor for my table
public TS_Question()
{
this._TS_Options = new EntitySet<TS_Option>(new Action<TS_Option>(this.attach_TS_Options), new Action<TS_Option>(this.detach_TS_Options));
this._TS_QuestGroups = new EntitySet<TS_QuestGroup>(new Action<TS_QuestGroup>(this.attach_TS_QuestGroups), new Action<TS_QuestGroup>(this.detach_TS_QuestGroups));
this._TS_QuestRecords = new EntitySet<TS_QuestRecord>(new Action<TS_QuestRecord>(this.attach_TS_QuestRecords), new Action<TS_QuestRecord>(this.detach_TS_QuestRecords));
this._TS_Admin = default(EntityRef<TS_Admin>);
this._TS_LevelType = default(EntityRef<TS_LevelType>);
this._TS_OptionTypeLT = default(EntityRef<TS_OptionTypeLT>);
OnCreated();
}
我创建的构造函数
public TS_Question(Guid Quest_QuestIDBL, string Quest_NameBL, Nullable<Guid> Quest_OptionTypeIDBL, Guid Quest_AdminIDBL, Guid Ques_LevelIDBL, int Quest_TimeBL, int Quest_MarkBL, string Qest_ExplanationBL, Nullable<bool> Qest_IsMultipleAnswerBL)
{
this._TS_Options = new EntitySet<TS_Option>(new Action<TS_Option>(this.attach_TS_Options), new Action<TS_Option>(this.detach_TS_Options));
this._TS_QuestGroups = new EntitySet<TS_QuestGroup>(new Action<TS_QuestGroup>(this.attach_TS_QuestGroups), new Action<TS_QuestGroup>(this.detach_TS_QuestGroups));
this._TS_QuestRecords = new EntitySet<TS_QuestRecord>(new Action<TS_QuestRecord>(this.attach_TS_QuestRecords), new Action<TS_QuestRecord>(this.detach_TS_QuestRecords));
this._TS_Admin = default(EntityRef<TS_Admin>);
this._TS_LevelType = default(EntityRef<TS_LevelType>);
this._TS_OptionTypeLT = default(EntityRef<TS_OptionTypeLT>);
OnCreated();
this._Quest_QuestID = Quest_QuestIDBL;
this._Quest_Name = Quest_NameBL;
if (Quest_OptionTypeIDBL != null)
{
this._Quest_OptionTypeID = Quest_OptionTypeIDBL;
}
this._Quest_AdminID = Quest_AdminIDBL;
this._Ques_LevelID = Ques_LevelIDBL;
this._Quest_Time = Quest_TimeBL;
this._Quest_Mark = Quest_MarkBL;
this._Qest_Explanation = Qest_ExplanationBL;
this._Qest_IsMultipleAnswer = Qest_IsMultipleAnswerBL;
}
请帮我解决这个问题
答案 0 :(得分:2)
老实说,我看起来并不太深,但看起来OnCreated坐在远北方......你可能想在设置变量后调用它。除此之外,我要说确保你正确地初始化调用构造函数的方法中的所有内容。
答案 1 :(得分:2)
您可以像这样调用默认构造函数,它对我来说很好用:
public partial class MyClass
{
public MyClass(string fieldValue1,int fieldValue2)
: this()
{
this.field1= fieldValue1;
this.field2 = fieldValue2;
}
}
如果这样做,您可以阅读有关在C#here中使用构造函数的更多信息。